欧拉计划(python) problem 1

problem 1

If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.

Find the sum of all the multiples of 3 or 5 below 1000.

python code:

k3=0;

k5=0;

result=0;

for i in range(1,1000):

k3=k3+1

k5=k5+1

if k3%3==0:

k3=0

result+=i

continue

if k5%5==0:

k5=0

result+=i

continue

print(result)

输出结果： 233168

大概用时：小于1s