I Can Guess the Data Structure!
There is a bag-like data structure, supporting two operations:
1 x
Throw an element x into the bag.
2
Take out an element from the bag.
Given a sequence of operations with return values, you‘re going to guess the data structure. It is a stack (Last-In, First-Out), a queue (First-In, First-Out), a priority-queue (Always take out larger elements first)
or something else that you can hardly imagine!
Input
There are several test cases. Each test case begins with a line containing a single integer n (1<=n<=1000). Each of the next n lines is either a type-1 command, or an integer 2 followed by an integer x. That means
after executing a type-2 command, we get an element x without error. The value of x is always a positive integer not larger than 100. The input is terminated by end-of-file (EOF). The size of input file does not exceed 1MB.
Output
For each test case, output one of the following:
stack
It‘s definitely a stack.
queue
It‘s definitely a queue.
priority queue
It‘s definitely a priority queue.
impossible
It can‘t be a stack, a queue or a priority queue.
not sure
It can be more than one of the three data structures mentioned above.
Sample Input
6 1 1 1 2 1 3 2 1 2 2 2 3 6 1 1 1 2 1 3 2 3 2 2 2 1 2 1 1 2 2 4 1 2 1 1 2 1 2 2 7 1 2 1 5 1 1 1 3 2 5 1 4 2 4
Output for the Sample Input
queue not sure impossible stack priority queue
Rujia Liu‘s Present 3: A Data Structure Contest Celebrating the 100th Anniversary of Tsinghua University
Special Thanks: Yiming Li
Note: Please make sure to test your program with the gift I/O files before submitting!
题目意思很简单,思路也很简单,直接模拟判断就是啦。。。。。
code:
#include<cstdio> #include<cstring> #include<iostream> #include<algorithm> #include<cmath> #include<stack> #include<queue> using namespace std; const int maxn=1010; int a[maxn],b[maxn]; int n; bool fs() { stack<int > s; for(int i=1;i<=n;i++) { if(a[i]==1) { s.push(b[i]); } else { if(s.empty()) return false; int d=s.top(); if(d!=b[i]) { return false; } else { s.pop(); } } } return true; } bool fq() { queue<int > q; for(int i=1;i<=n;i++) { if(a[i]==1) { q.push(b[i]); } else { if(q.empty()) return false; int d=q.front(); if(d!=b[i]) { return false; } else { q.pop(); } } } return true; } bool fQ() { priority_queue<int,vector<int>,less<int> >Q; for(int i=1;i<=n;i++) { if(a[i]==1) { Q.push(b[i]); } else { if(Q.empty()) return false; int d=Q.top(); if(d!=b[i]) { return false; } else { Q.pop(); } } } return true; } int main() { while(scanf("%d",&n)==1) { for(int i=1;i<=n;i++) { scanf("%d%d",&a[i],&b[i]); } bool flag1=fs(),flag2=fq(),flag3=fQ(); if(flag1==false&&flag2==false&&flag3==false) { printf("impossible\n"); } else if(flag1==true&&flag2==false&&flag3==false) { printf("stack\n"); } else if(flag1==false&&flag2==true&&flag3==false) { printf("queue\n"); } else if(flag1==false&&flag2==false&&flag3==true) { printf("priority queue\n"); } else { printf("not sure\n"); } } return 0; }