eg_1

1. 编写一个程序，输出一个字符串中的大写英文字母个数，小写英文字母个数以及非英文字母个数.

　　第一种方法：

public class Test {
	public static void main(String[] args) {
		String s = "[email protected]&&&haAA";
		int Lcount = 0, Ucount = 0, Ocount = 0;
		for(int i=0;i<s.length();i++){
			if(s.charAt(i) >= ‘a‘ && s.charAt(i) <= ‘z‘){
				Lcount++;
			}
			else if(s.charAt(i) >= ‘A‘ && s.charAt(i) <= ‘Z‘){
				Ucount++;
			}
			else {
				Ocount++;
			}
		}
		System.out.println("Lcount: "+Lcount+","+"Ucount: "+Ucount+","+"Ocount: "+Ocount);
	}
} //Lcount: 22,Ucount: 10,Ocount: 17

　　第二种方法：

public class Test {
	public static void main(String[] args) {
		String s = "[email protected]&&&haAA";
		int Lcount = 0, Ucount = 0, Ocount = 0;
		for(int i=0;i<s.length();i++){
			if(Character.isLowerCase(s.charAt(i))){
				Lcount++;
			}
			else if(Character.isUpperCase(s.charAt(i))){
				Ucount++;
			}
			else {
				Ocount++;
			}
		}
		System.out.println("Lcount: "+Lcount+","+"Ucount: "+Ucount+","+"Ocount: "+Ocount);
	}
}// Lcount: 22,Ucount: 10,Ocount: 17

第三种方法：

public class Test {
	public static void main(String[] args) {
		String BL = "abcdefghijklmnopqrstuvwxyz";
		String BU = "ABCDEFGHIJKLMNOPQRSTUVWXYZ";
		String s = "[email protected]&&&haAA";
		int Lcount = 0, Ucount = 0, Ocount = 0;
		for(int i=0;i<s.length();i++){
			if(BL.indexOf(s.charAt(i)) != -1){
				Lcount++;
			}
			else if(BU.indexOf(s.charAt(i)) != -1){
				Ucount++;
			}
			else {
				Ocount++;
			}
		}
		System.out.println("Lcount: "+Lcount+","+"Ucount: "+Ucount+","+"Ocount: "+Ocount);
	}
}// Lcount: 22,Ucount: 10,Ocount: 17