请编写程序，生成随机密码。具体要求如下：????????????????????????????????????????????????????????????????????????????????????????????????
（1）使用 random 库，采用 0x1010 作为随机数种子。????????????????????????????????????????????????????????????????????????????????????????????????
（2）密码 [email protected]#$%^&* 中的字符组成。????????????????????????????????????????????????????????????????????????????????????????????????
（3）每个密码长度固定为 10 个字符。????????????????????????????????????????????????????????????????????????????????????????????????
（4）程序运行每次产生 10 个密码，每个密码一行。????????????????????????????????????????????????????????????????????????????????????????????????
（5）每次产生的 10 个密码首字符不能一样。????????????????????????????????????????????????????????????????????????????????????????????????
（6）程序运行后产生的密码保存在“随机密码.txt”文件中。????????????????????????????????????????????????????????????????????????????????????????????????
????????????????????????????????????????????????????????????????????????????????????????????????
不写入文件，直接 print 10 个密码即可自动评阅
解析：
通读题目要求，req5是个难点，如何保证产生的10个密码首字符不同？
一个自然的想法是记录并比较
进而对于req4，就不能用for循环固定循环次数，需要用while循环
while循环退出循环的依据是什么？取决于如何记录密码，比如把每次生成的密码记录到一个列表，用len(ls)<10做退出循环的条件
每次生成的密码设为cipher,考虑以及几点
1.如何生成2.如何满足req5.3如何输出
1.如何生成，可以考虑用s[random.randint(0,len(s)-1)]或random.choice(s), s 是字符集
2.如何满足req5,可以记录每个cipher的首字符，并记录在字符串execlude,只有满足的才添加到ls中
3. 输出，每个密码一行，cipher+ ‘\n‘就可以了
具体代码如下：
import random
fo = open(‘D:/bak/skydrive/automation/2级/execise/随机密码.txt‘,‘w‘)
random.seed(0x1010)
s = ‘[email protected]#$%^&*‘
cipher = ‘‘ # store a cipher,store it into ls and then clear it
ls = [] # store all 10 cipher, len(ls) to count the num of cipher
execlude = ‘‘ # store the first char of a cipher,make sure the cipher meet req#5
while len(ls) < 10: # generate 10 cipher, not use for loop as due to req#5, the running time is not predictable
cipher = ‘‘ # reset cipher each round
for i in range(10): # 10个字符
#cipher += random.choice(s) # pickup a random char from s by random.choice and then connect cyper by +
cipher += s[random.randint(0,len(s)-1)]
cipher = cipher + ‘\n‘
if cipher[0] in execlude:
continue
else:
ls.append(cipher)
execlude += cipher[0]
#fo.writelines(cipher) # if write line by line,the performance is somewhat poor,let write the ls to file directly
#print(c)
print(‘‘.join(ls))
##for line in ls:
## fo.write(line)
fo.write(‘‘.join(ls))
#print(execlude)
fo.close()
执行结果：
So2WpkoC7i armJ86eUG9 B*GcqsYC^B wQ3bcfcAJy Xdyg8pQTIS YO!1YH1AP3 cu[email protected]& [email protected]$TBfp TBm#WfYNHr Ue75y$E9Cv
由此，可见2级综合编程题，需要在较短时间内，能解读问题，综合应用各种基本编程技能，完成题目要求，对初学者还是有一定难度的。
需要仔细审题，吃透题意，提高基本数据处理的熟练度，才能从容过关。
原文地址：https://www.cnblogs.com/jamesxu/p/11079893.html