USE AdventureWorks2012; GO SELECT f.name AS foreign_key_name ,OBJECT_NAME(f.parent_object_id) AS table_name ,COL_NAME(fc.parent_object_id, fc.parent_column_id) AS constraint_column_name ,OBJECT_NAME (f.referenced_object_id) AS referenced_object ,COL_NAME(fc.referenced_object_id, fc.referenced_column_id) AS referenced_column_name ,is_disabled ,delete_referential_action_desc ,update_referential_action_desc FROM sys.foreign_keys AS f INNER JOIN sys.foreign_key_columns AS fc ON f.object_id = fc.constraint_object_id WHERE f.parent_object_id = OBJECT_ID(‘HumanResources.Employee‘);转自:http://msdn.microsoft.com/zh-cn/library/ms190196.aspx
时间: 2024-11-12 22:56:37