POJ-2485 Highways + POJ-1258 Agri-Net 【Kruskal】

整理板子的时候翻出来的题，放在一起写是因为都是Kruskal纯板子题。

 1 #include<cstdio>
 2 #include<cstring>
 3 #include<iostream>
 4 #include<algorithm>
 5 #include<cmath>
 6 #include<string>
 7 #include<stack>
 8 #include<queue>
 9 #include<vector>
10 #include<cstdlib>
11 //#include<windows.h>
12 #define first fi
13 #define second se
14 using namespace std;
15 typedef long long ll;
16 const int N = 1e6+10;
17 const int INF = 0x3f3f3f3f;
18 const int inf = - INF;
19 const int mod = 1e9+7;
20 const double pi = acos(-1.0);
21 int n,m;
22 int father[505];
23 void init(){
24     m=0;
25     memset(father,-1,sizeof(father));
26 }
27 struct node {
28     int u,v,w;
29     node(){}
30     node(int u,int v, int w):u(u),v(v),w(w){}
31     bool operator < (const node &rhs)const{
32         return w < rhs.w;
33     }
34 }edge[N];
35 int Find(int x){
36     return father[x]==-1?x:father[x]=Find(father[x]);
37 }
38 int Kruskal(){
39     int maxn=-1;
40     int cnt=0;
41     for(int i=0;i<m;i++){
42         int u=edge[i].u;
43         int v=edge[i].v;
44         if(Find(u)!=Find(v)){
45             father[Find(u)]=Find(v);
46             maxn=max(maxn,edge[i].w);
47             if(++cnt>=n-1) return maxn;
48         }
49     }
50     return -1;
51 }
52 int main(){
53     int T;
54     scanf("%d",&T);
55     while(T--){
56         scanf("%d",&n);
57         init();
58         int t;
59         for(int i=1;i<=n;i++){
60             for(int j=1;j<=n;j++){
61                 scanf("%d",&t);
62                 edge[m++]=node(i,j,t);
63             }
64         }
65         sort(edge,edge+m);
66         printf("%d\n",Kruskal());
67     }
68     //system("pause");
69     return 0;
70 }

1258可以直接用2485改改就交，注意要多组输入。

#include<cstdio>
#include<cstring>
#include<iostream>
#include<algorithm>
#include<cmath>
#include<string>
#include<stack>
#include<queue>
#include<vector>
#include<cstdlib>
#include<windows.h>
#define first fi
#define second se
using namespace std;
typedef long long ll;
const int N = 1e6+10;
const int INF = 0x3f3f3f3f;
const int inf = - INF;
const int mod = 1e9+7;
const double pi = acos(-1.0);
ll n,m;
ll father[505];
void init(){
    m=0;
    memset(father,-1,sizeof(father));
}
struct node {
    ll u,v,w;
    node(){}
    node(ll u,ll v, ll w):u(u),v(v),w(w){}
    bool operator < (const node &rhs)const{
        return w < rhs.w;
    }
}edge[N];
ll Find(int x){
    return father[x]==-1?x:father[x]=Find(father[x]);
}
ll Kruskal(){
    ll sum=0;
    ll cnt=0;
    for(ll i=0;i<m;i++){
        ll u=edge[i].u;
        ll v=edge[i].v;
        if(Find(u)!=Find(v)){
            father[Find(u)]=Find(v);
            sum+=edge[i].w;
            if(++cnt>=n-1) return sum;
        }
    }
    return -1;
}
int main(){
    //int T;
    //scanf("%d",&T);
    while(~scanf("%lld",&n)){//注意多组输入
        init();
        ll t;
        for(ll i=1;i<=n;i++){
            for(ll j=1;j<=n;j++){
                scanf("%lld",&t);
                edge[m++]=node(i,j,t);
            }
        }
        sort(edge,edge+m);
        printf("%d\n",Kruskal());
    }
    system("pause");
    return 0;
}

原文地址：https://www.cnblogs.com/yoshinaripb/p/11786041.html