问题描述
搜索输入框中,只当用户停止输入后,才进行后续的操作,比如发起Http请求等。
学过电子电路的同学应该知道按键防抖。原理是一样的:就是说当调用动作n毫秒后,才会执行该动作,若在这n毫秒内又调用此动作则将重新计算执行时间。本文将分别探讨在angular.js和vue.js中如何实现对用户输入的防抖。
angular.js中解决方案
把去抖函数写成一个service,方便多处调用:
.factory('debounce', ['$timeout','$q', function($timeout, $q) {
// The service is actually this function, which we call with the func
// that should be debounced and how long to wait in between calls
return function debounce(func, wait, immediate) {
var timeout;
// Create a deferred object that will be resolved when we need to
// actually call the func
var deferred = $q.defer();
return function() {
var context = this, args = arguments;
var later = function() {
timeout = null;
if(!immediate) {
deferred.resolve(func.apply(context, args));
deferred = $q.defer();
}
};
var callNow = immediate && !timeout;
if ( timeout ) {
$timeout.cancel(timeout);
}
timeout = $timeout(later, wait);
if (callNow) {
deferred.resolve(func.apply(context,args));
deferred = $q.defer();
}
return deferred.promise;
};
};
}])
调用方法,在需要使用该功能的controller/directive中注入debounce,也要注入$watch,然后:
$scope.$watch('searchText',debounce(function (newV, oldV) {
console.log(newV, oldV);
if (newV !== oldV) {
$scope.getDatas(newV);
}
}, 350));
大功告成!
Vue.js中的解决方案
首先在公共函数文件中注册debounce
export function debounce(func, delay) {
let timer
return function (...args) {
if (timer) {
clearTimeout(timer)
}
timer = setTimeout(() => {
func.apply(this, args)
}, delay)
}
}
然后在需要使用的组件中引入debounce,并且在created生命周期内调用:
created() {
this.$watch('searchText', debounce((newSearchText) => {
this.getDatas(newSearchText)
}, 200))
}
大功告成!
引用
1. https://stackoverflow.com/questions/29771011/angularjs-watch-with-debounce
2. https://www.cnblogs.com/fsjohnhuang/p/4147810.html
原文地址:https://segmentfault.com/a/1190000012751237
原文地址:https://www.cnblogs.com/lalalagq/p/9959876.html
时间: 2024-11-20 08:10:30