一、django 1 版本
routers.py
import re from collections import OrderedDict from django.conf import settings from django.utils.module_loading import import_string # 根据字符串的形式,帮我们去导入模块 from django.urls import RegexURLResolver, RegexURLPattern # 路由分发:URLResolver。不是路由分发:URLPattern def check_url_exclude(url): """ 排除一些特定的url :param url: :return: """ exclude_url = [ ‘/admin.*‘, ‘/login/‘ ] for regex in settings.AUTO_DISCOVER_EXCLUDE: if re.match(regex, url): return True def recursion_urls(pre_namespace, pre_url, urlpatterns, url_ordered_dict): """ :param pre_namespace: namespace前缀(rbac:......),以后用于拼接name :param pre_url: url的前缀(rbac/......),以后用于拼接url :param urlpatterns: 路由关系列表 :param url_ordered_dict: 用于保存递归中获取的所有路由 :return: """ for item in urlpatterns: if isinstance(item,RegexURLPatter): # 非路由分发,将路由添加到url_ordered_dict if not item.name: # url中反向命名的name continue if pre_namespace: name = f"{pre_namespace}:{item.name}" else: name = item.name url = pre_url + item.item._regex # /^rbac/^user/edit/(?P<pk>\d_+)/$ url = url.replace(‘^‘, ‘‘).replace(‘$‘, ‘‘) # /rbac/user/edit/(?P<pk>\d_+)/ if check_url_exclude(url): continue url_ordered_dict[name] = {‘name‘: name, ‘url‘: url} elif isinstance(item, RegexURLResolver): # 路由分发,进行递归操作 if pre_namespace: if item.namespace: namespace = f"{pre_namespace}:{item.namespace}" else: namespace = item.namespace else: if item.namespace: namespace = item.namespace else: namespace = None recursion_urls(namespace, pre_url + item.regex.pattern, item.url_patterns, url_ordered_dict) def get_all_url_dict(): """ 获取项目中所有的URL(必须有name别名) :return: """ url_ordered_dict = OrderedDict() """ { ‘rbac:menu_list‘:{name:‘rbac:menu_list‘,url:‘xxxxx/yyyy/menu/list‘} } """ md = import_string(settings.ROOT_URLCONF) # from permision_learn import urls recursion_urls(None, ‘/‘, md.urlpatterns, url_ordered_dict) # 递归的去获取所有的路由。根目录没有namespace,根路由用/ return url_ordered_dict
views.py
def multi_permissions(request): """ 批量操作权限 :param request: :return: """ # 获取项目中所有的url all_url_dict = get_all_url_dict() for k, v in all_url_dict.items(): print(k, v) return HttpResponse(‘....‘)
二、django 2版本
django 2版本有些坑,和django 1版本的用法略有不同。谷歌查了半天,只查到模块名变了,没查到用法。没办法,只能取看源码,只能看到参数名变了,瞎试了试,居然能用。
routers.py
import re from collections import OrderedDict from django.conf import settings from django.utils.module_loading import import_string # 根据字符串的形式,帮我们去导入模块 from django.urls import URLPattern, URLResolver # 路由分发:URLResolver。不是路由分发:URLPattern def check_url_exclude(url): """ 排除一些特定的url :param url: :return: """ exclude_url = [ ‘/admin.*‘, ‘/login/‘ ] for regex in settings.AUTO_DISCOVER_EXCLUDE: if re.match(regex, url): return True def recursion_urls(pre_namespace, pre_url, urlpatterns, url_ordered_dict): """ :param pre_namespace: namespace前缀(rbac:......),以后用于拼接name :param pre_url: url的前缀(rbac/......),以后用于拼接url :param urlpatterns: 路由关系列表 :param url_ordered_dict: 用于保存递归中获取的所有路由 :return: """ for item in urlpatterns: if isinstance(item, URLPattern): # 非路由分发,将路由添加到url_ordered_dict if not item.name: # url中反向命名的name continue if pre_namespace: name = f"{pre_namespace}:{item.name}" else: name = item.name url = pre_url + item.pattern.regex.pattern # /^rbac/^user/edit/(?P<pk>\d_+)/$ url = url.replace(‘^‘, ‘‘).replace(‘$‘, ‘‘) # /rbac/user/edit/(?P<pk>\d_+)/ if check_url_exclude(url): continue url_ordered_dict[name] = {‘name‘: name, ‘url‘: url} elif isinstance(item, URLResolver): # 路由分发,进行递归操作 if pre_namespace: if item.namespace: namespace = f"{pre_namespace}:{item.namespace}" else: namespace = item.namespace else: if item.namespace: namespace = item.namespace else: namespace = None recursion_urls(namespace, pre_url + item.pattern.regex.pattern, item.url_patterns, url_ordered_dict) def get_all_url_dict(): """ 获取项目中所有的URL(必须有name别名) :return: """ url_ordered_dict = OrderedDict() """ { ‘rbac:menu_list‘:{name:‘rbac:menu_list‘,url:‘xxxxx/yyyy/menu/list‘} } """ md = import_string(settings.ROOT_URLCONF) # from permision_learn import urls recursion_urls(None, ‘/‘, md.urlpatterns, url_ordered_dict) # 递归的去获取所有的路由。根目录没有namespace,根路由用/ return url_ordered_dict
views.py
def multi_permissions(request): """ 批量操作权限 :param request: :return: """ # 获取项目中所有的url all_url_dict = get_all_url_dict() for k, v in all_url_dict.items(): print(k, v) return HttpResponse(‘....‘)
原文地址:https://www.cnblogs.com/lshedward/p/10467931.html
时间: 2024-11-05 21:38:45