解题报告 『占卜DIY（模拟）』

原题地址

水题，纯模拟。

代码实现如下：

#include <bits/stdc++.h>
using namespace std;
#define rep(i, a, b) for (register int i = a; i <= b; i++)
#define per(i, a, b) for (register int i = a; i >= b; i--)

const int maxn = 15;

int ans = 0;
int num[maxn], mat[maxn], poker[maxn][maxn];

int judge(char ch) {
    if (ch >= ‘0‘ && ch <= ‘9‘) return 0;
    if (ch == ‘A‘ || ch == ‘J‘ || ch == ‘Q‘ || ch == ‘K‘) return 0;
    return 1;
}

int get_char(char ch) {
    if (ch == ‘A‘) return 1;
    if (ch == ‘0‘) return 10;
    if (ch == ‘J‘) return 11;
    if (ch == ‘Q‘) return 12;
    if (ch == ‘K‘) return 13;
    return ch - ‘0‘;
}

void write(int x) {
    if (x < 0) {
        putchar(‘-‘);
        x = -x;
    }
    if (x > 9) write(x / 10);
    putchar(x % 10 + ‘0‘);
}

int main() {
    rep(i, 1, 13)
        per(j, 4, 1) {
            char ch = getchar();
            if (judge(ch)) ch = getchar();
            poker[i][j] = get_char(ch);
        }
    num[13] = 4;
    while (num[13]) {
        int now = poker[13][num[13]];
        num[13]--;
        while (now != 13) {
            mat[now]++;
            num[now]++;
            now = poker[now][num[now]];
        }
    }
    rep(i, 1, 12) ans += (mat[i] == 4);
    write(ans);
    return 0;
}

原文地址：https://www.cnblogs.com/Kirisame-Marisa/p/10803524.html