计算两个矩形的重合面积
import math x1, y1, x2, y2 = input().split(" ") x1, y1, x2, y2=int(x1), int(y1), int(x2), int(y2) # print(x1, y1, x2, y2) x1,x2 = min(x1,x2),max(x1,x2) y1,y2= min(y1,y2),max(y1,y2) # print(x1, y1, x2, y2) x3, y3, x4, y4 = input().split(" ") x3, y3, x4, y4 = int(x3), int(y3), int(x4), int(y4) x3,x4 = min(x3,x4),max(x3,x4) y3,y4 = min(y3,y4),max(y3,y4) # print(x3, y3, x4, y4) if (x2<=x3 or x4<=x1) and (y2 <= y3 or y4<=y1): print(0) else: lens = min(x2, x4) - max(x1, x3) wide = min(y2, y4) - max(y1, y3) print(lens*wide)
原文地址:https://www.cnblogs.com/chenpython123/p/11427275.html
时间: 2024-10-13 21:23:04