Closest In Sorted Array

Given a target integer T and an integer array A sorted in ascending order, find the index i in A such that A[i] is closest to T.

Assumptions

• There can be duplicate elements in the array, and we can return any of the indices with same value.

Examples

• A = {1, 2, 3}, T = 2, return 1
• A = {1, 4, 6}, T = 3, return 1
• A = {1, 4, 6}, T = 5, return 1 or 2
• A = {1, 3, 3, 4}, T = 2, return 0 or 1 or 2

Corner Cases

• What if A is null or A is of zero length? We should return -1 in this case.

 1 public int closest(int[] array, int target) {
 2     // Write your solution here
 3     if(array == null || array.length == 0) return -1 ;
 4     int left = 0 , right = array.length -1 ;
 5     while(left + 1< right){
 6         int mid = left +(right - left )/2 ;
 7       if(array[mid] == target) return mid ;
 8       if(array[mid]<target){
 9           left = mid ;
10       } else{
11           right = mid;
12       }
13     }
14     //post processing
15     if(Math.abs(array[left]-target)<= Math.abs(array[right] - target)){
16         return left ;
17     } else{
18         return right ;
19     }
20   }

原文地址：https://www.cnblogs.com/davidnyc/p/8468521.html