oracle 在xml中批量插入，批量修改及多组条件查询

最近公司用ibatis开发项目，本来可以用存储过程处理批量插入，批量修改及多组条件查询；但由于使用模块相对较小，暂时就在xml中配置，以前没有在xml做过类似处理，有必要记录一下；好了，代码如下：

<!-- 批量插入 -->
        <insert id="saveNotificationPushInfo" parameterClass="java.util.List">
            <![CDATA[INSERT ALL]]>
                <iterate conjunction="" >
                into notification_push_info(
                    push_log_no,
                    business_book,
                    employee_id,
                    notification_no,
                    push_flag,
                    push_time
                    )values
                    (
                    bep_seq_package.fetch_seq(‘NOTIFICATION_PUSH_INFO‘,‘PUSH_LOG_NO‘,‘BEPDATA‘),
                    #list[].businessBook:varchar#,
                    #list[].employeeId:varchar#,
                    #list[].notificationNo:varchar#,
                    #list[].pushFlag:varchar#,
                    sysdate
                )
                </iterate>
            <![CDATA[SELECT * FROM dual]]>
        </insert>

        <!-- 多组条件查询-->
        <select id="getSameNotificationList" parameterClass="java.util.List" resultClass="java.util.HashMap">
                select distinct employee_id "employeeId",
                                notification_no "notificationNo"
                from notification_push_info npi
                    where npi.invalid_flag = ‘N‘
            <iterate conjunction="or" open="and" close="">
                    npi.employee_id = #notiList[].employeeId#
                    and npi.business_book = #notiList[].businessBook#
                    and npi.notification_no = #notiList[].notificationNo#
            </iterate>
        </select>

        <!-- 批量修改-->
        <update id="updateNotiList" parameterClass="java.util.List">
            begin
            <iterate conjunction="">
                update notification_push_info set
                push_flag = #list[].FLAG#,
                push_time = sysdate
                where invalid_flag = ‘N‘
                and employee_id = #list[].employeeId#
                and notification_no = #notiList[].notificationNo#;
            </iterate>
            end;
        </update>

如有问题，请大家指出来，谢谢！

原文地址：https://www.cnblogs.com/lidelin/p/8270819.html