POJ 1007:DNA排序

AC CODE:

 1 import java.util.Scanner;
 2
 3 public class Main {
 4
 5     public static void main(String[] args) {
 6         Scanner input = new Scanner(System.in);
 7
 8         // 得到数据
 9         int n = input.nextInt();
10         int m = input.nextInt();
11         String temp = input.nextLine(); // 获得输入m后的换行符
12         String[] dna = new String[m];
13         for (int i = 0; i < m; i++) {
14             dna[i] = input.nextLine();
15         }
16
17         // 获得每个DNA串中逆序对的数量
18         int[] record = getInitInt(m);
19         for (int i = 0; i < m; i++) {
20             for (int j = 0; j < n; j++) {
21                 for (int k = j + 1; k < n; k++) {
22                     if (isBiggerChar(dna[i].charAt(j), dna[i].charAt(k))) {
23                         record[i]++;
24                     }
25                 }
26             }
27         }
28
29         // 得到这些DNA数列中最大的逆序对是多少
30         int max = -1;
31         for (int i = 0; i < m; i++) {
32             if (record[i] > max) {
33                 max = record[i];
34             }
35         }
36
37         // 得到这些DNA串中逆序对从小到大的一个顺序队列mark[]
38         int[] mark = new int[m];
39         for (int i = 0, k = 0; i <= max; i++) {
40             for (int j = 0; j < m; j++) {
41                 if (record[j] == i) {
42                     mark[k++] = j;
43                 }
44             }
45         }
46
47         // 打印
48         for (int i = 0; i < m; i++) {
49             System.out.println(dna[mark[i]]);
50         }
51
52     }
53
54     private static int[] getInitInt(int m) {
55         int[] record = new int[m];
56         for (int i = 0; i < m; i++) {
57             record[i] = 0;
58         }
59         return record;
60     }
61
62     private static boolean isBiggerChar(char a, char b) {
63         if ((a - b) > 0) {
64             return true;
65         }else {
66             return false;
67         }
68     }
69
70 }

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