Given a binary tree, return the inorder traversal of its nodes‘ values.
For example:
Given binary tree {1,#,2,3}
,
1 2 / 3
return [1,3,2]
.
Solution 1:
/** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: vector<int> inorderTraversal(TreeNode* root) { if(root != NULL) { inorderTraversal(root->left); v.push_back(root->val); inorderTraversal(root->right); } return v; } private: vector<int> v; };
Solution 2:
时间: 2024-11-01 14:10:49