暂未解决_调用构造函数进行类型转换

代码示例

 1 #include <iostream>
 2 using namespace std;
 3 class A
 4 {
 5 public:
 6     A(int x){ i = x; cout << "构造函数执行！" << i << endl; }
 7     ~A(){ cout << "析构函数执行！" << i << endl; }
 8     void get(){ cout << i << endl; }
 9 private:
10     int i;
11 };
12 int main()
13 {
14     A a(99);
15     a.get();
16     a = 1000;
17     a.get();
18     a = A(2);
19     a.get();
20     A b(35);
21     return 0;
22 }

输出结果