简单的排列组合-使用枚举

有五种颜色，每次取出三种，要求颜色无重复

 1 #include<stdio.h>
 2
 3 int main(void)
 4 {
 5     enum color{blue,red,yellow,purple,black};
 6     enum color i,j,k,pri;
 7
 8     int n,loop;
 9     n=0;
10
11     for(i=blue;i<=black;++i)
12     {
13         for(j=blue;j<=black;++j)
14         {
15             if(i!=j)
16             {
17                 for(k=blue;k<=black;++k)
18                 {
19                     if((k!=i)&&(k!=j))
20                     {
21                         ++n;
22                         printf("%-6d",n);
23                         for(loop=1;loop<=3;++loop)
24                         {
25                             switch(loop)
26                             {
27                                 case 1:pri=i;
28                                        break;
29                                 case 2:pri=j;
30                                        break;
31                                 case 3:pri=k;
32                                        break;
33                                 default:
34                                        break;
35                             }
36                             switch(pri)
37                             {
38                                 case blue:printf("%-10s","blue");
39                                           break;
40                                 case red :printf("%-10s","red");
41                                           break;
42                                 case yellow:printf("%-10s","yellow");
43                                             break;
44                                 case purple:printf("%-10s","pueple");
45                                             break;
46                                 case black:printf("%-10s","black");
47                                 default:
48                                            break;
49                             }
50                         }
51                         printf("\n");
52                     }
53                 }
54             }
55         }
56     }
57     printf("total : %5d\n",n);
58     return 0;
59 }