39. Combination Sum java solutions

Given a set of candidate numbers (C) and a target number (T), find all unique combinations in C where the candidate numbers sums to T.

The same repeated number may be chosen from C unlimited number of times.

Note:

  • All numbers (including target) will be positive integers.
  • The solution set must not contain duplicate combinations.

For example, given candidate set [2, 3, 6, 7] and target 7
A solution set is:

[
  [7],
  [2, 2, 3]
]
 1 public class Solution {
 2     public List<List<Integer>> ans = new ArrayList<List<Integer>>();
 3     public List<List<Integer>> combinationSum(int[] candidates, int target) {
 4         List<Integer> list = new ArrayList<Integer>();
 5         combination(list,candidates,target,0,0);
 6         return ans;
 7     }
 8
 9     public void combination(List<Integer> list, int[] can, int target, int sum, int s){
10         if(sum == target){
11             List<Integer> tmp = new ArrayList<Integer>(list);
12             ans.add(tmp);
13             return;
14         }
15         if(sum > target) return;
16         for(int i = s; i < can.length; i++){
17             list.add(can[i]);
18             combination(list,can,target,sum+can[i],i);
19             list.remove(list.size()-1);
20         }
21     }
22 }

都是套路。 N queen 问题掌握了就OK

时间: 2024-10-15 07:53:22

39. Combination Sum java solutions的相关文章

39. Combination Sum (Java)

Given a set of candidate numbers (candidates) (without duplicates) and a target number (target), find all unique combinations in candidates where the candidate numbers sums to target. The same repeated number may be chosen from candidates unlimited n

[LeetCode] Add to List 39. Combination Sum Java

题目:Given a set of candidate numbers (C) (without duplicates) and a target number (T), find all unique combinations in C where the candidate numbers sums to T. The same repeated number may be chosen from C unlimited number of times. Note: All numbers

[array] leetcode - 39. Combination Sum - Medium

leetcode - 39. Combination Sum - Medium descrition Given a set of candidate numbers (C) (without duplicates) and a target number (T), find all unique combinations in C where the candidate numbers sums to T. The same repeated number may be chosen from

刷题39. Combination Sum

一.题目说明 题目39. Combination Sum,是从正数列表中选取几个,其和等于目标数的可能组合.任何一个数可以重复取,如candidates = [2,3,6,7], target = 7,结果集合是[ [7], [2,2,3] ] 如candidates = [2,3,5], target = 8,结果集合是 [ [2,2,2,2], [2,3,3], [3,5] ] 题目难度是Medium,先思考一下,再来解答. 二.我的解答 经过一番思考,这个题目可以通过dfs(树的深度优先遍

[Leetcode][Python]39: Combination Sum

# -*- coding: utf8 -*-'''__author__ = '[email protected]' 39: Combination Sumhttps://oj.leetcode.com/problems/combination-sum/ Given a set of candidate numbers (C) and a target number (T),find all unique combinations in C where the candidate numbers

leetCode 39.Combination Sum(组合总和) 解题思路和方法

Combination Sum Given a set of candidate numbers (C) and a target number (T), find all unique combinations in C where the candidate numbers sums to T. The same repeated number may be chosen from C unlimited number of times. Note: All numbers (includi

39. Combination Sum I/II

基础backtracing题,先排序一下,每次传一个参数表示开始的下标. class Solution { public: vector<vector<int>> res; vector<vector<int>> combinationSum(vector<int>& candidates, int target) { sort(candidates.begin(),candidates.end()); vector<int>

Java [Leetcode 39]Combination Sum

题目描述: Given a set of candidate numbers (C) and a target number (T), find all unique combinations in C where the candidate numbers sums to T. The same repeated number may be chosen from C unlimited number of times. Note: All numbers (including target)

LeetCode 39. Combination Sum (组合的和)

Given a set of candidate numbers (C) (without duplicates) and a target number (T), find all unique combinations in C where the candidate numbers sums to T. The same repeated number may be chosen from C unlimited number of times. Note: All numbers (in