最近这几天的学习总练习:
#! /usr/bin/env python
# -*- coding: utf-8 -*-
# Date: 2017/6/9
#练习一/1:实现用户输入用户名和密码,当用户名为seven且密码为123时,显示登录成功,否则失败.
# d = {‘seven‘:‘123‘}
# while True:
# user = input(‘Enter your username:‘)
# passwd = input(‘Enter your password:‘)
# if not user and not passwd:
# continue
# elif user in d and passwd == d[user]:
# print(‘login ok‘)
# break
# else:
# print(‘login fail‘)
# 练习一/2:实现用户输入用户名和密码,当用户名为seven且密码为123时,显示登录成功,否则失败.允许失败是重复输入三次
# d = {‘seven‘:‘123‘}
# n = 0
# while n < 3:
# user = input(‘Enter your username:‘)
# passwd = input(‘Enter your password:‘)
# if not user and not passwd:
# continue
# elif user in d and passwd == d[user]:
# print(‘login ok‘)
# break
# else:
# print(‘login fail‘)
# n += 1
# 练习一/3:实现用户输入用户名和密码,当用户名为seven或alex且密码为123时,显示登录成功,否则失败.允许失败是重复输入三次
# d = {‘seven‘:‘123‘,‘alex‘:‘123‘}
# n = 3
# while n > 0 :
# user = input(‘Enter your username:‘)
# passwd = input(‘Enter your password:‘)
# if not user and not passwd:
# continue
# elif user in d and passwd == d[user]:
# print(‘login ok‘)
# break
# else:
# n -= 1
# print(‘You can also try to log in‘,n,‘times‘)
#练习二/1:使用while循环实现输出2-3+4-5+6...+100的和
# n = 2
# jsum = 0
# osum = 0
# while n < 101:
# if n % 2 == 1:
# jsum += n
# n += 1
# else:
# osum += n
# n += 1
# print(osum-jsum)
#练习二/2:使用for循环实现输出1-2+3-4+5-6..+99的和
# jsum = 0
# osum = 0
# for x in range(1,100):
# if x % 2 == 1:
# jsum += x
# else:
# osum += x
# print(osum-jsum)
#练习二/3:使用while循环实现输出1,2,3,4,5,7,8,9,11,12
# n = 1
# while n < 13:
# if n == 6 or n ==10:
# n += 1
# continue
# else:
# print(n,end = ‘ ‘)
# n += 1
#练习二/3:使用while循环实现输出1-100内的所有奇数
# n = 1
# while n < 101:
# if n % 2 == 1:
# print(n)
# n += 1
# else:
# n += 1
#练习二/3:使用while循环实现输出1-100内的所有偶数
# n = 1
# while n < 101:
# if n % 2 == 1:
# n += 1
# else:
# print(n)
# n += 1
# 练习三:
# name = " alex "
# a.移除name变量对应的值的两边的空格,并输入移除有的内容
# print(name.strip())
# b.判断name变量对应的值是否以"al"开头,并输出结果
# print(name.startswith(‘a1‘))
# c.判断name变量对应的值是否以"x"结尾,并输出结果
# print(name.endswith(‘x‘))
# d.将name变量对应的值中的"l"替换为"p",并输出结果
# print(name.replace(‘l‘,‘p‘))
# e.将name变量对应的值根据"l"分割,并输出结果
# print(name.split(‘l‘))
# f.请问,上一题e分割之后得到的值是什么类型
# print(type(name.split(‘e‘)))
# g.将name变量对应的值中变大写,并输出结果
# print(name.upper())
# h.将name变量对应的值中变大小写,并输出结果
# print(name.title())
# i.请输出name变量对应的值的第2个字符?
# print(name[1])
# j.请输出name变量对应的值的前3个字符?
# print(name[0:3])
# k.请输出name变量对应的值的后2个字符?
# print(name[0:-2])
# l.请输出name变量对应的值中"e"所在的索引位置?
# print(name.index(‘e‘))
# 练习四:
# 写代码,有如下列表,按照要求实现每一个功能
# li = [‘alex‘,‘eric‘,‘rain‘,‘abc‘,‘123‘,‘aaa‘]
# a.计算列表长度并输出
# print(len(li))
# b.列表中追加元素"seven",并输出添加后的列表
# li.append(‘seven‘)
# print(li)
# c.请在列表的第1个位置插入元素"Tony",并输出添加后的列表
# li.insert(1,‘Tony‘)
# print(li)
# d.请修改列表第2个位置的元素为"Kelly",并输出修改后的列表
# li[2]=‘Kelly‘
# print(li)
# e.请删除列表中的元素"eric",并输出修改后的列表
# li.remove(‘eric‘)
# print(li)
# f.请删除列表中的第2个元素,并输出删除元素的值和删除元素后的列表
# print(li.pop(1))
# print(li)
# g.请删除列表中的第3个元素,并输出删除元素后的列表
# li.pop(2)
# print(li)
# h.请删除列表中的第2至4个元素,并输出删除元素后的列表
# del li[2:5]
# print(li)
# i.请将列表所有的元素反转,并输出反转后的列表
# li.reverse()
# print(li)
# 练习五:
#正左直角
# for i in range(10):
# for j in range(0,i):
# print(‘*‘,end = ‘ ‘)
# print(‘‘)
#倒左直角
# for i in range(10):
# for j in range(0,10-i):
# print(‘*‘,end = ‘ ‘)
# print(‘‘)
#倒三角
# for i in range(10):
# for j in range(0,i):
# print(end = ‘ ‘)
# for k in range(0,10 - i):
# print(‘*‘,end = ‘ ‘)
# print(‘‘)
#正三角
# for i in range(10):
# for j in range(0,10 - i):
# print(end = ‘ ‘)
# for k in range(0,i):
# print(‘*‘,end = ‘ ‘)
# print(‘‘)
#九九乘法表
# for i in range(1,10):
# for j in range(1,i+1):
# print(‘%s*%s=%s‘%(i,j,i*j),end = ‘ ‘)
# print(‘‘)
# 练习六
#取出列表中的名字，年龄，出生的年，月，日
# data=[‘alex‘,49,[1900,3,18]]
# name,age,birthday = data=[‘alex‘,49,[1900,3,18]]
# print(name)
# print(age)
# print(birthday)
#去掉重复
# names=[‘egon‘,‘alex‘,‘egon‘,‘wupeiqi‘]
# name = set(names)
# print(name)
#去掉重复，且保证列表顺序与原来保持一致
# names=[‘egon‘,‘alex‘,‘egon‘,‘wupeiqi‘]
# tmp = []
# for n in names:
# if n not in tmp:
# tmp.append(n)
# print(tmp)
#去掉重复，且保证列表顺序与原来保持一致
# names=[[1,2],3,[1,2],4]
# tmp = []
# for n in names:
# if n not in tmp:
# tmp.append(n)
# print(tmp)
#统计s=‘hello alex alex say hello sb sb‘中每个单词的个数
# s=‘hello alex alex say hello sb sb‘
# l = s.split()
# st = set(l)
# for x in st:
# print(x,‘的个数为‘,l.count(x))
# for x in s:
# print(len(x))
#练习七
#not and or 的优先级是 not>and>or 既优先判断 not 没有not判断 and 没有and 最后判断 or,如果有括号先判断括号内的
# if True or False and False:
# print(‘yes‘)
# else:
# print(‘no‘)
#输出结果为?为什么? True or False ===> True 结果为:yes
# if (True or False) and False:
# print(‘yes‘)
# else:
# print(‘no‘)
#输出结果为?为什么? True and False ===> False 结果为:no
#练习八
#编写if多分支,猜老男孩的年纪
# age = int(input(‘Please enter your age:‘))
# tag = True
# while tag:
# user_input = input(‘Please enter your answer:‘)
# if user_input.isdigit():
# user_input = int(user_input)
# else:
# continue
# if int(user_input) > age:
# print(‘Guess big!‘)
# elif int(user_input) < age:
# print(‘Guess small!‘)
# elif int(user_input) == age:
# print(‘Congratulations,you guessed it!‘)
# tag = False
#练习九
#用户输入用户名密码验证,验证通过后进入子循环,输入命令,命令若为q,则退出所有循环
# d = {‘abc‘:‘123‘}
# tag = True
# while tag:
# user = input(‘Please enter your username:‘)
# passwd = input(‘Please enter your password:‘)
# if user in d and passwd == d[user]:
# while tag:
# cmd = input(‘>>:‘)
# if cmd == ‘q‘:
# tag = False
# print(‘exit‘)
# else:
# print(cmd)
#练习十
#循环取出元组中所有元素:方式一:while和for(按照索引),方式二:不按照索引的方式
# t=(1,2,3,4,5,6,7,8,9)
# n = 0
# while n < len(t):
# print(t[n])
# n += 1
#
# for x in range(len(t)):
# print(t[x])
#
# for x in t:
# print(x)
#练习十一
#循环读取列表以及子列表中所有元素
# l=[1,2,[3,4],[5,6]]
# for l in l:
# if type(l) == list:
# for s in l:
# print(s)
# else:
# print(l)
#练习十二#数据类型练习题:
# 有十进制数n=10
# 转成二进制
# print(bin(10))
# 转成八进制
# print(oct(10))
# 转成十六进制
# print(hex(10))
#练习十三
#与用户交互,要求用户输入年龄和薪资,将用户输入的年龄转成整形,将用户输入的薪资转成浮点型
# age = int(input(‘Plese enter your age:‘))
# salary = float(input(‘Please enter your salary:‘))
# print(‘age:‘,age,‘salary:‘,salary)
#练习十四
# 用户输入用户名,年纪,工作,爱好,格式化输出如下内容(使用%s和format两种方式)
# ------------ info of Alex Li -----------
# Name : Alex Li
# Age : 22
# job : Teacher
# Hobbie: girl
# ------------------ end -----------------
# name = input(‘Please enter your name:‘)
# age = input(‘Please enter your age:‘)
# job = input(‘Please enter your job:‘)
# hobby = input(‘Please enter your hobbies:‘)
# print(‘------------ info of %s -----------‘%name)
# print(‘‘‘Name:%s
# Age:%s
# Job:%s
# Hobby:%s
# ‘‘‘%(name,age,job,hobby),end = ‘‘)
# print(‘------------------ end -----------------‘)
# print(‘------------ info of %s -----------‘%name)
# info = ‘‘‘Name:{a}
# Age:{b}
# Job:{c}
# Hobby:{d}
# ‘‘‘
# print(info.format(a = name,b = age,c = job,d = hobby),end = ‘‘)
# print(‘------------------ end -----------------‘)
#练习十五
# s=‘alex say hello‘
# 切片取出第say
# s = s.split()
# print(s[1])
# 切片取出倒数后两个字符
# s = s.split()
# print(s[1:3])
#练习十六
# 编写循环,让用户输入年纪,如果输入为空,或者不为数字,则重新输入
# tag = True
# while tag:
# age = input(‘Please enter your age:‘)
# if age.isdigit():
# print(‘age:‘,age)
# tag = False
# 练习十七
# 用列表模拟上电梯的流程(队列)
# 循环生成一个1000个值的列表(入队)
# 循环取走这个1000个值(出队)
# l = []
# n = 0
# for x in range(1000):
# l.append(x)
# while n < 1000:
# print(l.pop(0))
# n += 1
# 用列表模拟把衣服放箱子里,然后取衣服的流程(堆栈)
# 循环生成一个1000个值的列表(入栈)
# 循环取走这个1000个值(出栈)
# l = []
# n = 0
# for x in range(1000):
# l.append(x)
# while n < 1000:
# print(l.pop())
# n += 1
#练习十八
# dicta={‘a‘:1,‘b‘:2,‘c‘:3,‘d‘:‘hello‘}
# dictb={‘b‘:3,‘c‘:2,‘d‘:‘world‘,‘f‘:10}
#两字典相加,不同的key对应的值保留,相同的key对应的值相加后保留,如果是字符串就拼接(字符串拼接‘hello‘+‘world‘得‘helloworld‘)
# {‘a‘: 1, ‘b‘: 5, ‘c‘: 5, ‘d‘: ‘helloworld‘, ‘f‘: 10}
# d = {}
# d.update(dicta)
# for k2,v2 in dictb.items():
# if k2 not in d:
# d[k2] = v2
# elif k2 in d:
# d[k2] = d[k2]+v2
# print(d)
#练习十九 #此题egon老师未出完.
#alex发表了朋友圈:
# alex_msg=‘‘‘
# 我想淫一首小诗
# 歌颂我的同桌
# 她乌黑的头发
# 好像一直炸毛鸡
# ‘‘‘
#
#eogn发表了朋友圈:
# egon_msg=‘‘‘
# 总有文盲装文艺
# ‘‘‘
# comments={
# alex_msg:{
# ‘author‘:‘alex‘,
# ‘comments‘:[
# (‘wupeiqi‘,‘真傻比‘),
# (‘元昊‘,‘确实傻比‘),
# (‘egon‘,‘同上‘)
# ],
# ‘thumb_counts‘:3,
# },
# egon_msg:{
# ‘author‘:‘egon‘,
# ‘comments‘:[
# (‘alex‘,‘说谁呢‘),
# (‘元昊‘,‘你被开除了‘),
# (‘wupeiqi‘,‘好刺激‘)
# ],
# ‘thumb_counts‘:2,
# },
# }
#
#循环打印出朋友圈内容
# tag = True
# while tag:
# cmd = input(‘查看朋友圈?(y/n)‘)
# if cmd == ‘y‘:
# for k1,v1 in comments.items():
# print(k1)
# for k2,v2 in v1.items():
# if type(v2) == list:
# for u,s in v2:
# print(‘%s:%s‘%(u,s))
# elif type(v2) != list:
# print(‘%s:%s‘%(k2,v2))
# tag = False
时间： 2024-08-06 16:06:44