第一个方法: #include <iostream> #include <string> using namespace std; int main(){ int n, h, t, o; cin >> n; h = n / 100; // 对于每位数的求解不能出错 t = n / 10 % 10; o = n % 100 % 10; if (h != 0){ // 要使用连续的是那个if,而不是 else if for (int i = 0; i < h; i++) cout << ‘B‘; } if (t != 0){ for (int j = 0; j < t; j++) cout << ‘S‘; } if (o != 0){ for (int k = 1; k <= o; k++) cout << k; } cout << endl; return 0; } 第二个方法: #include <iostream> using namespace std; int main() { int n, i = 0, a[10] = {0}; cin >> n; while (n != 0)。// 利用已经给定的条件,巧妙设置 { a[i++] = n % 10; n /= 10; } for (int j = i; j >= 0; j--) { for (int k = 0; k < a[j]; k++) { if (j == 2) cout << "B"; if (j == 1) cout << "S"; if (j == 0) { for (int l = 1; l <= a[j]; l++) { cout << l; } break; } } } cout << endl; return 0; }
原文地址:https://www.cnblogs.com/Hk456/p/10714370.html
时间: 2024-11-08 07:01:39