LeetCode 796. Rotate String

原题链接在这里:https://leetcode.com/problems/rotate-string/

题目:

We are given two strings, A and B.

shift on A consists of taking string A and moving the leftmost character to the rightmost position. For example, if A = ‘abcde‘, then it will be ‘bcdea‘ after one shift on A. Return True if and only if A can become B after some number of shifts on A.

Example 1:
Input: A = ‘abcde‘, B = ‘cdeab‘
Output: true

Example 2:
Input: A = ‘abcde‘, B = ‘abced‘
Output: false

Note:

  • A and B will have length at most 100.

题解:

Like this rotate question, we could double it by A + A.

And check if B is within A + A.

Time Complexity: O(n). n = A.length().

Space: O(n).

AC Java:

1 class Solution {
2     public boolean rotateString(String A, String B) {
3         if(A == null || B == null || A.length() != B.length()){
4             return false;
5         }
6
7         return (A + A).indexOf(B) != -1;
8     }
9 }

原文地址:https://www.cnblogs.com/Dylan-Java-NYC/p/12539138.html

时间: 2024-08-13 10:20:49

LeetCode 796. Rotate String的相关文章

[LeetCode&Python] Problem 796. Rotate String

We are given two strings, A and B. A shift on A consists of taking string A and moving the leftmost character to the rightmost position. For example, if A = 'abcde', then it will be 'bcdea' after one shift on A. Return True if and only if A can becom

796. Rotate String

We are given two strings, A and B. A shift on A consists of taking string A and moving the leftmost character to the rightmost position. For example, if A = 'abcde', then it will be 'bcdea' after one shift on A. Return True if and only if A can becom

796. Rotate String旋转字符串

[抄题]: We are given two strings, A and B. A shift on A consists of taking string A and moving the leftmost character to the rightmost position. For example, if A = 'abcde', then it will be 'bcdea' after one shift on A. Return True if and only if A can

[LC] 796. Rotate String

We are given two strings, A and B. A shift on A consists of taking string A and moving the leftmost character to the rightmost position. For example, if A = 'abcde', then it will be 'bcdea' after one shift on A. Return True if and only if A can becom

LeetCode算法题-Rotate String(Java实现)

这是悦乐书的第317次更新,第338篇原创 在开始今天的算法题前,说几句,今天是世界读书日,推荐两本书给大家,<终身成长>和<禅与摩托车维修艺术>,值得好好阅读和反复阅读. 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第186题(顺位题号是796).给定两个字符串A和B,在A上进行移位操作,规则是将A最左边的字符移动到最右边去.例如,如果A ='abcde',那么在A上移位一次后,它将是'bcdea'.当且仅当A在A上移位一定次数后可以变为B时返回True.

LeetCode --- 61. Rotate List

题目链接:Rotate List Given a list, rotate the list to the right by k places, where k is non-negative. For example: Given 1->2->3->4->5->NULL and k = 2, return 4->5->1->2->3->NULL. 这道题的要求是向右旋转链表k步. 其实就是把链表后面l-k个节点放到前面,可以采用快慢指针处理.不

【Leetcode】Rotate Image

You are given an n x n 2D matrix representing an image. Rotate the image by 90 degrees (clockwise). Follow up: Could you do this in-place? 思路:第一种思路是一层一层的进行旋转,比较直观:第二种思路则比较取巧,首先沿着副对角线翻转一次,然后沿着水平中线翻转一次. 代码一: class Solution { public: void rotate(vector<

[LeetCode 题解]: Rotate List

Given a list, rotate the list to the right by k places, where k is non-negative. For example:Given 1->2->3->4->5->NULL and k = 2,return 4->5->1->2->3->NULL. 题意: 翻转链表. 思路: 首先需要读懂题意.题目的描述有问题,应该是将链表的最后k个元素移动到链表的头部. 这道题的本质就是寻找链表的

Rotate String

Given a string and an offset, rotate string by offset. (rotate from left to right) Example Given "abcdefg". offset=0 => "abcdefg" offset=1 => "gabcdef" offset=2 => "fgabcde" offset=3 => "efgabcd&quo