UT源代码 159

设计佣金问题的程序

commission方法是用来计算销售佣金的需求，手机配件的销售商，手机配件有耳机（headphone）、手机壳（Mobile phone shell）、手机贴膜（Cellphone screen protector）三个部件，每个部件单价为：耳机80元，手机壳10元，手机贴膜8元，每月月末向制造商报告销量，制造商根据销量给销售商佣金。如果销售额不足1000元按10%提取佣金，1000-1800元部分按15%提取佣金，超过1800元部分按20%提取佣金。

程序要求：

1）先显示“请分别输入三种手机配件的销售情况：”

2）不满足条件，返回：“输入数量不满足要求”，返回重新输入；

3）条件均满足， 则返回佣金额。返回等待输入。

package demo;
 2
 3 import java.io.BufferedReader;
 4 import java.io.InputStreamReader;
 5
 6 public class Commission {
 7     public static final int Pheadphone = 80;
 8     public static final int Pshell = 10;
 9     public static final int Pprotector = 8;
10
11     private static BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(System.in));
12
13     private static int headphone = -1;
14     private static int shell = -1;
15     private static int protector = -1;
16
17     public static double commission(int headphone,int shell,int protector){
18         double sum = 0;
19         double salary = 0.0;
20         sum = Pheadphone*headphone + Pshell*shell +Pprotector*protector;
21         if(sum<1000)
22             salary = 0.1*Pheadphone*headphone + 0.1*Pshell*shell +0.1*Pprotector*protector;
23         else if(sum<1800)
24             salary = 0.15*Pheadphone*headphone + 0.15*Pshell*shell +0.15*Pprotector*protector;
25         else
26             salary = 0.2*Pheadphone*headphone + 0.2*Pshell*shell +0.2*Pprotector*protector;
27         return salary;
28     }
29     private static int[] input(){
30         int a[] = null, i = 0;
31         try {
32             String str = bufferedReader.readLine();
33             String s[] = str.split("\\s+");
34             a = new int[s.length];
35             for(String tmp : s){
36                 a[i++] = Integer.parseInt(tmp);
37             }
38         } catch (Exception e) {
39             a = null;
40         }
41         return a;
42     }
43     public static void main(String[] args) {
44
45         double salary = 0.0;
46         int exit = 1, a[] = null;
47         while(exit == 1){
48             System.out.println("请分别输入三种手机配件的销售情况：");
49             while(a == null){
50                 a = input();
51                 if(a == null || a.length != 3){
52                     System.out.println("输入数量不满足要求”，返回重新输入: ");
53                 }else{
54                     headphone = a[0];
55                     shell = a[1];
56                     protector = a[2];
57                 }
58             }
59             if(headphone<0||shell<0||protector<0){
60                 System.out.println("输入数量不满足要求");
61                 continue;
62             }
63             salary = commission(headphone,shell,protector);
64             System.out.println("佣金额为："+salary);
65             headphone = shell = protector = -1;
66             a = null;
67         }
68     }
69
70 }