LeetCode算法题python解法:23. Merge k Sorted Lists

Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity.

Example:

Input:
[
  1->4->5,
  1->3->4,
  2->6
]
Output: 1->1->2->3->4->4->5->6

题目大意就是给定多个已经排序的链表合并成一个排序的链表,我这里是将多个链表的值遍历添加到一个链表中,然后重新组织链表。复杂多比较高代码如下:
class Solution:
    def mergeKLists(self, lists):
        if lists == []:
            return None
        link = []
        for i in lists:
            while i != None:
                link.append(i.val)
                if i.next == None:
                    break
                i = i.next
        link = sorted(link)
        print(link)
        if len(link) == 0:
            return None
        out = [ListNode(link[0])]
        for i in range(1, len(link)):
            out.append(ListNode(link[i]))
            out[i - 1].next = out[i]

        out.append(ListNode(link[-1]))
        return out[0]

原文地址:https://www.cnblogs.com/slarker/p/9759799.html

时间: 2024-07-31 02:07:14

LeetCode算法题python解法:23. Merge k Sorted Lists的相关文章

leetcode 刷题之路 93 Merge k Sorted Lists

Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. 将k个有序链表合并成一个有序链表. 思路,之前做过两个有序链表的合并操作,对于k个链表,我们最先想到的就是能不能转化为我们熟悉的两个链表的合并,可以我们先将k个链表分为两部分,先对这两部分完成链表的有序合并操作,再对合并得到的两个链表进行合并,这是一个递归性质的描述,采用递归很容易实现这个程序,和数组

[LeetCode]23. Merge k Sorted Lists

23. Merge k Sorted Lists Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. 给定k个排序了的链表,合并k个链表成一个排序链表. 本程序思路: 1)首先得到K个链表的长度和存在len中 2)从K个链表中找到值最小的那个节点,把该节点添加到合并链表中 3)重复len次即可把所有节点添加到合并链表中. 注意事项: 1)K个链表中有的

23. Merge k Sorted Lists - LeetCode

Question 23.?Merge k Sorted Lists Solution 题目大意:合并链表数组(每个链表中的元素是有序的),要求合并后的链表也是有序的 思路:遍历链表数组,每次取最小节点 Java实现: public ListNode mergeKLists(ListNode[] lists) { ListNode preHead = new ListNode(0); ListNode minNode = getMinNode(lists); ListNode tmpNode =

#23 Merge k Sorted Lists (N路归并排序)

#23 Merge k Sorted Lists (N路归并排序) 题目地址:#23 题目分类:链表/归并排序/堆排序 题目难度:hard 题目 Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. 翻译:合并K个已经排序的链表,返回一个排序好的链表. 思路 暴力法,我们很容易想到:以一个for循环遍历所有的链表,找出最小的,然后将这个节点加入新的链表

23. Merge k Sorted Lists(js)

23. Merge k Sorted Lists Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. Example: Input: [   1->4->5,   1->3->4,   2->6 ] Output: 1->1->2->3->4->4->5->6题意:按大小顺序合并n条链表代码

[Leetcode][Python]23: Merge k Sorted Lists

# -*- coding: utf8 -*-'''__author__ = '[email protected]' 23: Merge k Sorted Listshttps://oj.leetcode.com/problems/merge-k-sorted-lists/ Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. ===Comments by

【一天一道LeetCode】#23. Merge k Sorted Lists

一天一道LeetCode系列 (一)题目 Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. (二)解题 合并K个已拍好序的链表.剑指上有合并两个已排好序的链表的算法,那么K个数,我们可以采用归并排序的思想,不过合并函数可能需要修改一下,换成合并两个已排好序的链表的方法.代码如下: /** * Definition for singly-linked

leetCode 23. Merge k Sorted Lists (合并k个排序链表) 解题思路和方法

Merge k Sorted Lists Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. 思路:此题是由合并两个排序链表演化而来,刚开始,想法比较简单,像求最大公共前缀一样,逐一求解:但是最后超时,所以马上意识到出题方是为了使用归并和分治的方法,故重新写了代码. 代码一(超时未过): /** * Definition for singly-link

LeetCode 23 Merge k Sorted Lists (C,C++,Java,Python)

Problem: Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. Solution: 采用胜者树的方法,胜者树介绍:胜者树,假如链表数组长度为n,链表元素总个数为k,那么时间复杂度为O(k*log(n)) 题目大意: 给定一个数组有序链表(数组元素可能为空),要求将这些链表合并为一个有序的链表. Java源代码(522ms): /** * Defi