821. Shortest Distance to a Character

 1 class Solution
 2 {
 3 public:
 4     vector<int> shortestToChar(string S, char C)
 5     {
 6         int len=S.length();
 7         vector<int>res(len,-1);                   //as the result vector
 8         vector<int> cindex;                       //save the index of C
 9         for(int i=0;i<len;i++)                    //write the distance of C and build the cindex
10             if(S[i]==C)
11             {
12                 cindex.push_back(i);
13                 res[i]=0;
14             }
15         int szindex=cindex.size();
16
17         int count=1;
18         for(int j=cindex[0]-1;j>=0;j--)           //write the distance before the first C
19             res[j]=count++;
20
21         count=1;
22         for(int k=cindex[szindex-1]+1;k<len;k++)  //write the distance after the last C
23             res[k]=count++;
24
25         for(int x=1;x<szindex;x++)                //write the distance between two C
26         {
27             count=1;
28             int left=cindex[x-1]+1,right=cindex[x]-1;
29             while(left<=right)
30             {
31                 res[left++]=count;
32                 res[right--]=count++;
33             }
34         }
35         return res;
36     }
37 };

原文地址:https://www.cnblogs.com/zhuangbijingdeboke/p/9189307.html

时间: 2024-11-08 19:08:45

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