超级水的一道题。上题目

Problem Description

A median in a sequence with the length of
n
is an element which occupies position number ?n+12?
after we sort the elements in the non-decreasing order (the elements are numbered starting with 1). A median of an array (2, 6, 1, 2, 3) is the number 2, and a median of array (0, 96, 17, 23) — the number 17.

An average of a sequence is the sum of sequence divided the size of the sequence.

Goffi likes median very much and he hates average number. So if a sequence‘s average number is larger than or equal to the median of sequence, Goffi will hate the sequence. Otherwise, Goffi will like it.

Now, your are given a sequence. Please find whether Goffi will like it or hate it.

Input

Input contains multiple test cases (less than 100). For each test case, the first line contains an integer
n
(1≤n≤1000),
indicating the size of the sequence. Then in the next line, there are
n
integers a1,a2,…,an
(1≤ai≤1000),
seperated by one space.

Output

For each case, if Goffi like the sequence, output "YES" in a line. Otherwise, output "NO".

Sample Input

5
1 2 3 4 5
4
1 5 6 6

Sample Output

NO
YES

让你判断五个数中（N+1）/2的位置这个数是否大于这五个数的平均数。大于就YES，反之NO。（坑点，要将五个数排序。）

上代码

#include <string.h>
#include <algorithm>
#include <stdio.h>
using namespace std;
int main()
{
    double a[1050];
    int n,i;
    while(~scanf("%d",&n))
    {
        memset(a,0,sizeof(a));
        double sum=0;
        for(i=1;i<=n;i++)
        {
            scanf("%lf",&a[i]);
            sum+=a[i];
        }
        sum=sum/n;
        sort(a+1,a+n+1);
        int mid=(n+1)/2;
        if(sum<a[mid])
            printf("YES\n");
        else
            printf("NO\n");
    }
    return 0;
}