转自:http://www.cnblogs.com/losesea/archive/2013/06/14/3134900.html
题目:有以下2个二维数组
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$a=Array(0 => Array(id => 66,class_name => www.iiwnet.com),1 => Array(id => 67,class_name => linux ));
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$b=Array(0 => Array(class_count=> 8),1 => Array(class_count => 2));
两个数组内容如上,如何把$a和$b合并成为一个新的二维数组,要求新数组内容如下:
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Array(0 => Array(id => 66,class_name => www.iiwnet.com,class_count=> 8),1 => Array(id => 67,class_name => linux ,class_count => 2));
这个题目一定有人遇到过 正好今天群里有人问 就给出2种解法
以下代码由 PHP教程网 原创提供
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方法一:
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function arrpreg(){
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$a=Array(0 => Array(id => 66,class_name => www.iiwnet.com),1 => Array(id => 67,class_name => linux ));
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$b=Array(0 => Array(class_count=> 8),1 => Array(class_count => 2));
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$arr = array();
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foreach ($a as $k => $r) {
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foreach($r as $k1 => $r1){
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$arr[$k][$k1] = $r1;
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}
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}
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foreach ($b as $k => $r) {
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foreach($r as $k1 => $r1){
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$arr[$k][$k1] = $r1;
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}
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}
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return $arr;
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}
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$ar= arrpreg();
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echo ‘<pre>‘;
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print_r($ar);
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echo ‘</pre>‘;
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?>
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方法二:
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$a = array(0 => Array(id => 66,class_name => www.iiwnet.com),1 => Array(id => 67,class_name => linux ));
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$b = array(0 => Array(class_count=> 8),1 => Array(class_count => 2));
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$arr = array();
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foreach($a as $k=>$r){
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$arr[] = array_merge($r,$b[$k]);
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}
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echo ‘<pre>‘;
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print_r($arr);
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echo ‘</pre>‘;
转自http://www.2cto.com/kf/201210/159324.html
PHP二维数组合并,根据某个key合并
最终解决方案:
- /**
- *
- * @param type $v 要传入的组合阵列
- * @param type $keyname 对应的KEY名称。
- * @param type $valname 要写入的值KEY名称
- * @param type $s 重组译的阵例。预设空值。
- */
- function test($v,$keyname,$valname,$s=Array())
- {
- foreach($v AS $_k => $d)
- {
- $s[$d[$keyname]][$valname]= $d[$valname];
- }
- return $s;
- }
- $key =‘server_id‘;
- foreach($arr1 as $k=>$v){
- $arr[$v[‘server_id‘]]= $v;
- }
- $data = test($arr2,$key,‘arr2‘,$arr);
- $data = test($arr3,$key,‘arr3‘,$data);