题目链接：http://acm.hdu.edu.cn/showproblem.php?pid=4801

题面：

Pocket Cube

Time Limit: 20000/10000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)

Problem Description

Pocket Cube is a 3-D combination puzzle. It is a 2 × 2 × 2 cube, which means it is constructed by 8 mini-cubes. For a combination of 2 × 2 mini-cubes which sharing a whole cube face, you can twist it 90 degrees in clockwise or counterclockwise
direction, this twist operation is called one twist step.

Considering all faces of mini-cubes, there will be totally 24 faces painted in 6 different colors (Indexed from 0), and there will be exactly 4 faces painted in each kind of color. If 4 mini-cubes‘ faces of same color rely on same large cube face, we can call
the large cube face as a completed face.

Now giving you an color arrangement of all 24 faces from a scrambled Pocket Cube, please tell us the maximum possible number of completed faces in no more than N twist steps.

Index of each face is shown as below:

Input

There will be several test cases. In each test case, there will be 2 lines. One integer N (1 ≤ N ≤ 7) in the first line, then 24 integers Ci separated by a single space in the second line. For index 0 ≤ i < 24, Ci is color of the
corresponding face. We guarantee that the color arrangement is a valid state which can be achieved by doing a finite number of twist steps from an initial cube whose all 6 large cube faces are completed faces.

Output

For each test case, please output the maximum number of completed faces during no more than N twist step(s).

Sample Input

1
0 0 0 0 1 1 2 2 3 3 1 1 2 2 3 3 4 4 4 4 5 5 5 5
1
0 4 0 4 1 1 2 5 3 3 1 1 2 5 3 3 4 0 4 0 5 2 5 2

Sample Output

6
2

Source

2013 Asia Changsha Regional Contest

解题：

转魔方，注意对应位置别弄错就好，深搜，广搜都可以。就是比较难调。

总结：

一些重复性代码，最好写成函数调用，减少代码的冗余性，同时提高代码的准确性。

代码：

#include <iostream>
#include <cstdio>
using namespace std;
int cube[24],tmp,a,b,c,ans,n;
int check()
{
	int res=0;
	tmp=cube[0];
	if(tmp==cube[1]&&tmp==cube[2]&&tmp==cube[3])res++;
	tmp=cube[4];
	if(tmp==cube[5]&&tmp==cube[10]&&tmp==cube[11])res++;
	tmp=cube[6];
	if(tmp==cube[7]&&tmp==cube[12]&&tmp==cube[13])res++;
    tmp=cube[8];
	if(tmp==cube[9]&&tmp==cube[14]&&tmp==cube[15])res++;
    tmp=cube[16];
	if(tmp==cube[17]&&tmp==cube[18]&&tmp==cube[19])res++;
    tmp=cube[20];
	if(tmp==cube[21]&&tmp==cube[22]&&tmp==cube[23])res++;
    return res;
}
void rotate(int oper)
{
    if(oper==1)
	{
		a=cube[1];
		b=cube[3];
		c=cube[9];
		cube[1]=cube[7];
		cube[3]=cube[13];
		cube[7]=cube[17];
		cube[13]=cube[19];
		cube[17]=cube[21];
		cube[19]=cube[23];
		cube[21]=a;
		cube[23]=b;
		cube[9]=cube[8];
		cube[8]=cube[14];
        cube[14]=cube[15];
		cube[15]=c;
	}
	else if(oper==6)
    {
		a=cube[7];
		b=cube[13];
		c=cube[14];
		cube[7]=cube[1];
		cube[13]=cube[3];
		cube[1]=cube[21];
		cube[3]=cube[23];
		cube[21]=cube[17];
		cube[23]=cube[19];
		cube[17]=a;
		cube[19]=b;
		cube[14]=cube[8];
		cube[8]=cube[9];
        cube[9]=cube[15];
		cube[15]=c;
	}
    else if(oper==2)
    {
		a=cube[8];
		b=cube[14];
		c=cube[7];
		cube[8]=cube[17];
		cube[14]=cube[16];
		cube[17]=cube[11];
		cube[16]=cube[5];
		cube[11]=cube[2];
		cube[5]=cube[3];
		cube[2]=a;
		cube[3]=b;
		cube[7]=cube[13];
		cube[13]=cube[12];
        cube[12]=cube[6];
		cube[6]=c;
	}
    else if(oper==5)
    {
		a=cube[16];
		b=cube[17];
		c=cube[12];
		cube[17]=cube[8];
		cube[16]=cube[14];
		cube[8]=cube[2];
		cube[14]=cube[3];
		cube[2]=cube[11];
		cube[3]=cube[5];
		cube[11]=b;
		cube[5]=a;
		cube[12]=cube[13];
		cube[13]=cube[7];
        cube[7]=cube[6];
		cube[6]=c;
	}
    else if(oper==3)
    {
		a=cube[12];
		b=cube[13];
		c=cube[16];
		cube[12]=cube[14];
		cube[13]=cube[15];
		cube[14]=cube[21];
		cube[15]=cube[20];
		cube[21]=cube[10];
		cube[20]=cube[11];
		cube[10]=a;
		cube[11]=b;
		cube[16]=cube[17];
		cube[17]=cube[19];
        cube[19]=cube[18];
		cube[18]=c;
	}
	else
    {
		a=cube[12];
		b=cube[13];
		c=cube[16];
		cube[12]=cube[10];
		cube[13]=cube[11];
		cube[10]=cube[21];
		cube[11]=cube[20];
		cube[20]=cube[15];
		cube[21]=cube[14];
		cube[14]=a;
		cube[15]=b;
		cube[16]=cube[18];
		cube[18]=cube[19];
        cube[19]=cube[17];
		cube[17]=c;
	}
}
void search(int oper,int step)
{
	rotate(oper);
	tmp=check();
	if(tmp>ans)ans=tmp;
    if(step==n)
	{
		rotate(7-oper);
		return;
	}
	for(int i=1;i<=6;i++)
	{
		if(i!=(7-oper))
		{
			search(i,step+1);
		}
	}
    rotate(7-oper);
}
int main()
{
	while(~scanf("%d",&n))
	{
		for(int i=0;i<24;i++)
			scanf("%d",&cube[i]);
        ans=check();
		for(int i=1;i<=6;i++)
			search(i,1);
		printf("%d\n",ans);
	}
	return 0;
}

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