数据处理4位树代码扩展为6位

原始数据

1    行政后勤            0001
2    院办                  000104810002
4    宣传室                000104810004
5    综合档案室            000104810005
6    收发室                000104810006
7    车队                000104810007
8    人力资源部        00010008
10    医院控制处        00010010
11    病案管理处        00010011
12    护理部            00010012
13    消毒供应中心    01720013
14    科教处            00010014
16    学院办公室        00010016
17    监察审计处        00010017
18    工会                00010018
19    团委                00010019
20    财务处                00010020
22    附二门诊收费处    000100200022
23    儿童门急诊            000100200023
24    附二住院收费处    000100200024
27    儿童住院收费处    000100200027

方法一：

;with tree as
(
   select ksdm,ksmc,
	case len(kswm) when 4 then ‘‘ when 8 then ‘00‘+substring(kswm,1,4) when 12 then ‘00‘+substring(kswm,5,4) when 16 then ‘00‘+substring(kswm,9,4) end as p,
	case len(kswm) when 4 then ‘00‘+kswm when 8 then ‘00‘+substring(kswm,5,4) when 12 then ‘00‘+substring(kswm,9,4) when 16 then ‘00‘+substring(kswm,13,4) end as c
    from ks
)
,cte as
(
	-->begin定位点
   select ksdm,ksmc,c as kswm,c,p,1 as levle from tree where p=‘‘
    -->end
   union all
    -->begin
   select tree.ksdm,tree.ksmc,cte.kswm+tree.c as kswm,tree.c,tree.p,levle+1 as levle from tree inner join cte on tree.p=cte.c
    -->end
)
select * from cte order by kswm

方法二：

Excel函数

=IF(LEN(C3)>4,CONCATENATE("00",MID(C3,5,4)),"")