判断 Android 手机是否处于联网状态

Android App的开发大多数情况下都要与网络进行连接，那如何判断网络是否连接，处于何种连接呢？下面是关于连接写的一个方法，可以根据需求做相应的修改：

private String connection(Context context) {//判断联网，一定要记得写权限<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE"></uses-permission>    String connectInfo = "网络未连接";    ConnectivityManager connect = (ConnectivityManager) context            .getSystemService(Context.CONNECTIVITY_SERVICE);    NetworkInfo info = connect.getActiveNetworkInfo();    if(info != null && info.isConnected()){    //if(info.isAvailable()){//此判断在使用时会有异常，需要处理        connectInfo = "网络已经连接，";

        //GPS是否打开        if(isGpsEnabled(this)){            connectInfo += "GPS已经开启";        }else {            connectInfo += "GPS未开启";        }

        //WiFi是否打开        if(isWifiEnabled(this,connect)){            connectInfo += "WIFI开启";        }else {            connectInfo += "WIFI未开启";        }

        int netType = info.getType();        if(netType == ConnectivityManager.TYPE_WIFI){            connectInfo += "\n当前使用WIFI";        }else if(netType == ConnectivityManager.TYPE_MOBILE){            connectInfo += "\n当前使用移动连接";        }else {            connectInfo += "\n当前使用连接是:"+netType;        }    }    return connectInfo;}

//判断GPS是否打开public static boolean isGpsEnabled(Context context) {    LocationManager lm = ((LocationManager) context            .getSystemService(Context.LOCATION_SERVICE));    List<String> accessibleProviders = lm.getProviders(true);    return accessibleProviders != null && accessibleProviders.size() > 0;}//判断WIFI是否打开public static boolean isWifiEnabled(Context context,ConnectivityManager mgrConn) {    TelephonyManager mgrTel = (TelephonyManager) context            .getSystemService(Context.TELEPHONY_SERVICE);    return ((mgrConn.getActiveNetworkInfo() != null && mgrConn            .getActiveNetworkInfo().getState() == NetworkInfo.State.CONNECTED) || mgrTel            .getNetworkType() == TelephonyManager.NETWORK_TYPE_UMTS);}