第二次作业+105032014020

测试结果链接：http://www.cnblogs.com/rcher/p/6592510.html

问题答复：

给出的绝大部分测试例子均能通过，改进建议只有一条，即对非法输入的判定，我认为这并不是原题目中功能要求的一部分，保证输入数据格式正确是前提条件，所以并未修改，而只是用java重构了一下代码。

 1 package main;
 2 import java.util.Scanner;
 3
 4 public class run {
 5     public static int month[]={0,31,28,31,30,31,30,31,31,30,31,30,31};
 6     public static int checkVal(int y,int m,int d)//check whether the inputs are legal or not
 7     {
 8         if(m<1||m>12)
 9             return 1;
10         if(d<1||d>month[m])
11             return 2;
12         if(y<1912||y>2050)
13             return 3;
14         return 0;
15     }
16
17     public static int checkLeapYear(int y) ////check if y year is leap year return 1 otherwise return 0
18     {
19          if(y%4==0&&y%100!=0)
20                 return 1;
21             if(y%100==0&&y%400==0)
22                 return 1;
23             return 0;
24     }
25     public static int checkLastday(int y,int m,int d)//check whether the date is the last day of a year,if it is return 1 otherwise return 0
26     {
27          if(m==12&&d==31)
28                 return 1;
29             else
30                 return 0;
31     }
32
33     public static String getString(int y,int m,int d)//generate date in string form
34     {
35         return y+"年"+m+"月"+d+"日";
36     }
37
38     public static String nextdate(int y,int m,int d)//calculate next date, result is presented in "xxxx年x月x日" form
39     {
40         if(checkLeapYear(y)==1)
41         {
42             month[2]=29;
43         }
44         switch (checkVal(y,m,d))
45         {
46             case 1:
47                 return "月份超出范围";
48             case 2:
49                 return "日期超出范围";
50             case 3:
51                 return "年份超出范围";
52             default:
53                 if(d<month[m]&&checkLastday(y,m,d)==0)
54                 {
55                     return getString(y, m, d+1);
56                 }
57                 if(d==month[m])
58                 {
59                     if(checkLastday(y, m, d)==1)
60                     {
61                         return getString(y+1, 1, 1);
62                     }
63                     else
64                     {
65                         return getString(y, m+1, 1);
66                     }
67                 }
68                 return "";
69         }
70     }
71     public static void main (String[] args)
72     {
73         while(true)
74         {
75             System.out.println("请输入日期");
76             int y,m,d;
77             Scanner input=new Scanner(System.in);
78             y=input.nextInt();
79             if(y==-1)
80                 break;
81             else
82             {
83                 m=input.nextInt();
84                 d=input.nextInt();
85                 System.out.println(nextdate(y,m,d));
86                 month[2]=28;
87             }
88         }
89     }
90 }