Given a Weather
table, write a SQL query to find all dates‘ Ids with higher temperature compared to its previous (yesterday‘s) dates.
+---------+------------+------------------+ | Id(INT) | Date(DATE) | Temperature(INT) | +---------+------------+------------------+ | 1 | 2015-01-01 | 10 | | 2 | 2015-01-02 | 25 | | 3 | 2015-01-03 | 20 | | 4 | 2015-01-04 | 30 | +---------+------------+------------------+
For example, return the following Ids for the above Weather table:
+----+ | Id | +----+ | 2 | | 4 | +----+ 查找与昨天的日期相比更高的日期的id。 MySQL(1868ms):
SELECT w1.Id FROM Weather w1 , Weather w2 WHERE w1.Temperature > w2.Temperature AND TO_DAYS(w1.Date) - TO_DAYS(w2.Date) = 1 ;
原文地址:https://www.cnblogs.com/mengchunchen/p/8321258.html
时间: 2024-09-30 15:29:39