Reverse Integer 解题总结

Reverse Integer Reverse digits of an integer. Example1: x = 123, return 321Example2: x = -123, return -321 click to show spoilers. SOLUTION 1: 注意越界后返回0.先用long来计算,然后,把越界的处理掉. public class Solution { public int reverse(int x) { long ret = 0; while (x !

1.题目名称 Reverse Integer(翻转数字) 2.题目地址 https://leetcode.com/problems/reverse-integer/ 3.题目内容 英文:Reverse digits of an integer. 中文:翻转一个正整数的各位,形成一个新数字 例如:x = 123, return 321:x = -123, return -321 4.一个有瑕疵的方法(不能AC) 一个比较好想到的方法,是先将输入的数字转换为字符串,再将字符串翻转后转换为数字.这个方

题目来源:https://leetcode.com/problems/reverse-integer/ Reverse digits of an integer. Example1: x = 123, return 321Example2: x = -123, return -321 解题思路: 其实这道题看起来非常简单,要实现也是几行代码的事.但是有个小问题容易被忽略,就是边界问题.什么意思呢?如果我们输入的整数超出了int的表达范围,这个问题要怎么解决呢? 用比int更大的数据类型存储我们转

题目 Reverse digits of an integer. Example1: x = 123, return 321 Example2: x = -123, return -321 click to show spoilers. Have you thought about this? Here are some good questions to ask before coding. Bonus points for you if you have already thought th

Reverse Integer Reverse digits of an integer. Example1: x = 123, return 321Example2: x = -123, return -321 若反转的数溢出,直接返回0 可以用计算结果来判断溢出,也可以用因数来判断 Java代码实现: 1 public class ReverseInteger { 2 public static int reverseInt(int x){ 3 if (x == 0) { 4 return

Reverse Integer Reverse digits of an integer. Example1: x = 123, return 321Example2: x = -123, return -321 click to show spoilers. Have you thought about this? Here are some good questions to ask before coding. Bonus points for you if you have alread

public class Solution { int reverse(int x) { long result = 0; while(x!=0){ result = result*10 + x%10 ; x/=10 ; } if(result>Integer.MAX_VALUE || result<Integer.MIN_VALUE ) return 0 ; else return (int)result ; } } https://leetcode.com/problems/reverse

[题目] Reverse digits of an integer. Example1: x = 123, return 321 Example2: x = -123, return -321 [题意] 反转int型整数,输出的也是int型的整数 [思路] 如要考虑两种特殊情况: 1. 类似100这样的整数翻转之后为1 2. 翻转之后的值溢出该如何处理, 本题的测试用例中似乎没有给出溢出的情况 在实际面试时需要跟面试官明确这种情况的处理方法. 基于这点事实,本题规定如果超出正边界返回INT_MA

Reverse digits of an integer. Returns 0 when the reversed integer overflows (signed 32-bit integer). Have you met this question in a real interview? Example Given x = 123, return 321 Given x = -123, return -321 LeetCode上的原题,请参见我之前的博客Reverse Integer.