leetcode Combination Sum II python

Given a collection of candidate numbers (C) and a target number (T), find all unique combinations in C where the candidate numbers sums to T.

Each number in C may only be used once in the combination.

Note:
All numbers (including target) will be positive integers.
Elements in a combination (a1, a2, … , ak) must be in non-descending order. (ie, a1 ≤ a2 ≤ … ≤ ak).
The solution set must not contain duplicate combinations.
For example, given candidate set 10,1,2,7,6,1,5 and target 8,
A solution set is:
[1, 7]
[1, 2, 5]
[2, 6]
[1, 1, 6]
Subscribe to see which companies asked this question

class Solution(object):
    def combinationSum2(self, candidates, target):
        """
        :type candidates: List[int]
        :type target: int
        :rtype: List[List[int]]
        """
        candidates.sort()
        self.ret=[]
        self.dfs(candidates,target,0,[])
        return self.ret
    def dfs(self,candidates,target,start,valuelist):
        intlen=len(candidates)
        if target == 0 and valuelist not in self.ret:
            self.ret.append( valuelist)
        for i in range(start,intlen):
            if target < candidates[i]:
                return
            self.dfs(candidates,target-candidates[i],i+1,valuelist+[candidates[i]])
时间: 2024-08-04 06:32:48

leetcode Combination Sum II python的相关文章

LeetCode: Combination Sum II [039]

[题目] Given a collection of candidate numbers (C) and a target number (T), find all unique combinations in C where the candidate numbers sums to T. Each number in C may only be used once in the combination. Note: All numbers (including target) will be

LeetCode: Combination Sum II 解题报告

Combination Sum II Given a collection of candidate numbers (C) and a target number (T), find all unique combinations in C where the candidate numbers sums to T. Each number in C may only be used once in the combination. Note:All numbers (including ta

[LeetCode] Combination Sum II 组合之和之二

Given a collection of candidate numbers (C) and a target number (T), find all unique combinations in C where the candidate numbers sums to T. Each number in C may only be used once in the combination. Note: All numbers (including target) will be posi

[Leetcode] Combination Sum II

Given a collection of candidate numbers (C) and a target number (T), find all unique combinations in C where the candidate numbers sums to T. Each number in C may only be used once in the combination. Note: All numbers (including target) will be posi

[LeetCode] Combination Sum II (递归)

Given a collection of candidate numbers (C) and a target number (T), find all unique combinations in C where the candidate numbers sums to T. Each number in C may only be used once in the combination. Note: All numbers (including target) will be posi

LeetCode——Combination Sum II

Given a collection of candidate numbers (C) and a target number (T), find all unique combinations in C where the candidate numbers sums to T. Each number in C may only be used once in the combination. Note: All numbers (including target) will be posi

LeetCode Combination Sum II (DFS)

题意: 在集合candidates中选出任意多个元素,使得他们的和为target,返回所有的组合,以升序排列. 思路: 难点在于如何去重,比如集合{1,1,2},target=3,那么只有一个组合就是1+2=3,而不是两个. DFS解决,每次考虑candidates[i]取还是不取,但是这样子还是会产生重复,这里只需要一个技巧就可以使得没有重复出现.如果当前元素已经被考虑过取了,那么在考虑不取的时候,i后面的与candidates[i]相同的都要跳过.观察一下可以发现,如果有一串相同的数字出现的

[leetcode] 040. Combination Sum II (Medium) (C++)

索引:[LeetCode] Leetcode 题解索引 (C++/Java/Python/Sql) Github: https://github.com/illuz/leetcode 040. Combination Sum II (Medium) 链接: 题目:https://leetcode.com/problems/combination-sum-ii/ 代码(github):https://github.com/illuz/leetcode 题意: 跟 039 一样(给出一些正整数集合,

[leetcode]Combination Sum @ Python

原题地址:https://oj.leetcode.com/problems/combination-sum/ 题意: Given a set of candidate numbers (C) and a target number (T), find all unique combinations in C where the candidate numbers sums to T. The same repeated number may be chosen from C unlimited