在根据网上的方法进行mvc ajax 提交form时成功后总是会跳转至一个空白界面并仅显示返回的数据，之后又经过多次查找资料找到了解决方法，具体用法如下（注意红色字体）
<head>
<script type="text/javascript" src="@Url.Content("~/scripts/jquery.form.min.js")"></script>
<meta name="viewport" content="width=device-width" />
<title>新增信息</title>
<script type="text/javascript">
$(function(){
var options = {
url:"/Info/Info_Add",
beforeSubmit: showRequest, //提交前处理
success: showResponse, //处理完成
resetForm: false
};
$(‘#info_form‘).submit(function() {
$(this).ajaxSubmit(options);
}).submit(function(){return false;});
});
function showRequest(formData, jqForm, options) {
alert("提请前");
return true;
}
function showResponse(data) {
if(data=="1")
{
alert("修改成功！");
}
}
</script>
</head>
<body>
<form id="info_form" name="info_form" action="/Info/Info_Add" method="post">
<table class="pure-table pure-table-horizontal">
<tr>
<td style="width: auto">案件编号：</td>
<td style="width: auto">@Html.TextBox("caseid", cid, new { disabled = "disabled", @readonly = "readonly" })</td>
</tr>
<tr> <td style="width: auto" align="center" colspan="2">
<input type="button" id="tolist" name="tolist" class="btn" value="查看已发布清单" style="display:none" onclick="location.href=‘@Url.Action("NewsList", "News") ‘" />
<input type="submit" value="添加" />
</td>
</tr>
</table>
</form>
</body>
control:
[HttpPost]
public ActionResult Info_Add(string id)
{
string s1=Request.Form["caseCusname"];
string rs = "1";
return Content(rs);
}
时间： 2025-01-09 10:33:31