按照字典的值进行排序

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from random import  randint

d= {k:randint(0,20) for k in ‘abcdefg‘}

#{‘f‘: 10, ‘g‘: 16, ‘a‘: 18, ‘c‘: 12, ‘e‘: 16, ‘d‘: 7, ‘b‘: 16}

z = list(zip(d.values(),d.keys()))

# zip函数就是将输入的序列重新组合成每个元素都是元组的列表，其中每个元素由输入序列相同位置的元素组成

#[(10, ‘f‘), (16, ‘g‘), (18, ‘a‘), (12, ‘c‘), (16, ‘e‘), (7, ‘d‘), (16, ‘b‘)]

print(sorted(zip(d.values(),d.keys())))

#[(7, ‘d‘), (10, ‘f‘), (12, ‘c‘), (16, ‘b‘), (16, ‘e‘), (16, ‘g‘), (18, ‘a‘)]

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print(sorted(d.items(),key = lambda k : k[1]))

#[(‘d‘, 7), (‘f‘, 10), (‘c‘, 12), (‘g‘, 16), (‘e‘, 16), (‘b‘, 16), (‘a‘, 18)]

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import operator

print(sorted(d.items(), key=operator.itemgetter(1)))

#[(‘d‘, 7), (‘f‘, 10), (‘c‘, 12), (‘g‘, 16), (‘e‘, 16), (‘b‘, 16), (‘a‘, 18)]