http://codeforces.com/problemset/problem/723/C
将n个数替换为1-m内的数,使得1-m的个数的最小值最大,并且替换步骤最少。注意,不必将每个数都替换!!
#include<iostream> #include<cstring> #include<cstdio> #include<algorithm> #include<cmath> #define INF 0x3f3f3f3f using namespace std; int a[2005],b[2005] = {0}; int main() { int m,n; scanf("%d%d",&n,&m); for(int i = 1;i <= n;i++) { scanf("%d",&a[i]); if(a[i] <= m) b[a[i]]++; } int ans = n/m; int cnt = 0; for(int i = 1;i <= n;i++) { if(a[i] > m || a[i] <= m && b[a[i]] > ans) { int j; for(j = 1;j <= m;j++) { if(b[j] < ans) break; } if(j == m+1) break; if(a[i] <= m) b[a[i]]--; a[i] = j; b[j]++; num++; } } printf("%d %d\n",ans,num); int flag = 1; for(int i = 1;i <= n;i++) { if(flag) { printf("%d",a[i]); flag = 0; } else { printf(" %d",a[i]); } } printf("\n"); return 0; }
时间: 2024-11-05 12:31:05