[LintCode] Longest Increasing Continuous Subsequence 最长连续递增子序列

Give an integer array，find the longest increasing continuous subsequence in this array.

An increasing continuous subsequence:

  • Can be from right to left or from left to right.
  • Indices of the integers in the subsequence should be continuous.
Notice

O(n) time and O(1) extra space.

Have you met this question in a real interview?

Yes

Example

For [5, 4, 2, 1, 3], the LICS is [5, 4, 2, 1], return 4.

For [5, 1, 2, 3, 4], the LICS is [1, 2, 3, 4], return 4.

时间： 2025-01-14 04:20:44

[LintCode] Longest Increasing Continuous Subsequence 最长连续递增子序列的相关文章

[LintCode] Longest Increasing Continuous Subsequence

Give an integer array,find the longest increasing continuous subsequence in this array. An increasing continuous subsequence: Can be from right to left or from left to right. Indices of the integers in the subsequence should be continuous. Example Fo

lintcode 容易题：Longest Increasing Continuous subsequence 最长上升连续子序列

题目: 最长上升连续子序列 给定一个整数数组(下标从 0 到 n-1, n 表示整个数组的规模),请找出该数组中的最长上升连续子序列.(最长上升连续子序列可以定义为从右到左或从左到右的序列.) 样例 给定 [5, 4, 2, 1, 3], 其最长上升连续子序列(LICS)为 [5, 4, 2, 1], 返回 4. 给定 [5, 1, 2, 3, 4], 其最长上升连续子序列(LICS)为 [1, 2, 3, 4], 返回 4. 解题: 这个直接找就可以了,最长的升序,和最长的降序,再求最大值,时

LintCode "Longest Increasing Continuous subsequence II" !!

DFS + Memorized Search (DP) class Solution { int dfs(int i, int j, int row, int col, vector<vector<int>>& A, vector<vector<int>>& dp) { if(dp[i][j] != 0) return dp[i][j]; if (i > 0 && A[i-1][j] > A[i][j]) { dp

Longest Increasing Continuous subsequence II

Give you an integer matrix (with row size n, column size m),find the longest increasing continuous subsequence in this matrix. (The definition of the longest increasing continuous subsequence here can start at any row or column and go up/down/right/l

Longest Increasing Continuous Subsequence

Give an integer array,find the longest increasing continuous subsequence in this array. An increasing continuous subsequence: Can be from right to left or from left to right. Indices of the integers in the subsequence should be continuous. Notice O(n

任意区间的最长连续递增子序列，最大连续子序列和

hdu3308 给n个数,有m个操作 U a b 表示将第a个数改成b Q a b 表示询问区间[a,b]的最长连续递增子序列. 区间询问问题且带修改,一般是用线段树来解决 那么要维护 Llen[rt], Lval[rt][2] 表示rt所对应的区间[l,r] 以l开头的最长连续递增子序列的长度, Lval[rt][0]表示子序列的最左边的值,Lval[rt][1]表示子序列最右边的值 Rlen[rt],Rval[rt][2]  表示rt所对应的区间[l,r]以r结尾的最长连续递增子序列的长度,

最长连续递增子序列（部分有序）

题目:(1,9,2,5,7,3,4,6,8,0,)中最长的递增子序列为(3,4,6,8). 代码: public class 最长递增子序列 { public static void main(String[] args) { int []arr = {1,0,2,5,7,3,4,6,8,9,1,2}; getLargestLen(arr); } private static void getLargestLen(int[] arr) { int begin=0; // 最长递增子序列长度的开始

【算法】——查找：最长连续递增子序列（部分有序）

找出在数组中的最长递增子序列 数组:1,9,2,5,7,3,4,6,8,0 最长递增子序列:3,4,6,8 思路: 遇到大的就移动,如果在某一个位置变小了就计算这一段的长度(双指针)不停更新最大的length一个在前线,一个在后面作为游标,最后结束了看一下战线拉了有多长 public class 最长递增子序列 { public static void main(String[] args) { int []arr = {0,1,0,1,2,3,1,2,0,1,2,3,4,5,1}; getLa

LeetCode 674. Longest Continuous Increasing Subsequence最长连续递增序列 (C++/Java)

题目: Given an unsorted array of integers, find the length of longest continuous increasing subsequence (subarray). Example 1: Input: [1,3,5,4,7] Output: 3 Explanation: The longest continuous increasing subsequence is [1,3,5], its length is 3. Even tho