再练一遍猜拳

{
        static void Main(string[] args)
        {
            while (true)
            {
                int x, y;
                string a, b;     //首先先随机生成三个数，然后将0,1,2变成剪刀石头布，利用switch case达到，在比较的时候注意当x为0，y为2的时候，出x的获胜。即先判断这一句   x == 0 && y == 2 ，这句成立直接输出，因为后面的是||或者的意思；y获胜也一样，即先判断x == 2 && y == 0这一句，如果不成立再判断下一句。

Random r = new Random();
                x = r.Next(0, 3);
                y = r.Next(0, 3);
                switch (x)
                {
                    case 0:
                        a = "剪刀";
                        break;
                    case 1:
                        a = "石头";
                        break;
                    case 2:
                        a = "布";
                        break;
                    default:
                        a = "耍赖";
                        break;
                       }
                switch (y)
                {
                    case 0:
                        b= "剪刀";
                        break;
                    case 1:
                        b = "石头";
                        break;
                    case 2:
                        b= "布";
                        break;
                    default:
                        b = "耍赖";
                        break;
                 }
                Console.WriteLine(a);
                Console.WriteLine(b);
                if (x == 0 && y == 2 || x > y)
                {
                    Console.WriteLine(a+"获胜");
                }
                else if (x == y)
                {
                    Console.WriteLine( "平局");
               
                }
                else if (x == 2 && y == 0 || x < y)
                {

Console.WriteLine(b + "获胜");

}

else
                {
                    Console.WriteLine("出现错误");
               
                }
               
               
                Console.ReadLine();

}

}
    }
}