Behind the scenes in the computer‘s memory, color is always talked about as a series of 24 bits of information for each pixel. In an image, the color with the largest proportional area is called the dominant color. A strictly dominant color takes more than half of the total area. Now given an image of resolution M by N (for example, 800x600), you are supposed to point out the strictly dominant color.
Input Specification:
Each input file contains one test case. For each case, the first line contains 2 positive numbers: M (<=800) and N (<=600) which are the resolutions of the image. Then N lines follow, each contains M digital colors in the range [0, 224). It is guaranteed that the strictly dominant color exists for each input image. All the numbers in a line are separated by a space.
Output Specification:
For each test case, simply print the dominant color in a line.
Sample Input:
5 3 0 0 255 16777215 24 24 24 0 0 24 24 0 24 24 24
Sample Output:
24
1 #include <stdio.h> 2 #include <stdlib.h> 3 #include <iostream> 4 #include <string.h> 5 6 #include <math.h> 7 #include <algorithm> 8 #include <vector> 9 #include <set> 10 #include <string> 11 #include <map> 12 using namespace std; 13 const int maxn=800*600+10; 14 15 16 int main(){ 17 int m,n; 18 scanf("%d %d",&m,&n); 19 map<int,int> count; 20 for(int i=0;i<n;i++) 21 { 22 for(int j=0;j<m;j++) 23 { 24 int temp; 25 scanf("%d",&temp); 26 if(count.find(temp)!=count.end()) 27 { 28 count[temp]++; 29 }else 30 { 31 count[temp]=1; 32 } 33 } 34 } 35 int k=0,max=0; 36 for(map<int,int>::iterator it=count.begin();it!=count.end();it++) 37 { 38 if(it->second>max) 39 { 40 k=it->first; 41 max=it->second; 42 } 43 } 44 printf("%d",k); 45 return 0; 46 }