Django2.0异常:Specifying a namespace in include() without providing an app_name is not supported.
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Django2.0异常:Specifying a namespace in include() without providing an app_name is not supported.编辑器
在CRM项目权限分配管理中
用django设置好了URL后报错。URL代码为
from django.conf.urls import url,include
from django.contrib import admin
urlpatterns = [
url(r‘^admin/‘, admin.site.urls),
url(r‘^rbac/‘, include(‘rbac.urls‘,namespace=‘rbac‘)),
url(r‘^‘, include(‘web.urls‘)),
]
源码为
def include(arg, namespace=None):
app_name = None
if isinstance(arg, tuple):
# Callable returning a namespace hint.
try:
urlconf_module, app_name = arg
except ValueError:
if namespace:
raise ImproperlyConfigured(
‘Cannot override the namespace for a dynamic module that ‘
‘provides a namespace.‘
)
raise ImproperlyConfigured(
‘Passing a %d-tuple to include() is not supported. Pass a ‘
‘2-tuple containing the list of patterns and app_name, and ‘
‘provide the namespace argument to include() instead.‘ % len(arg)
)
else:
# No namespace hint - use manually provided namespace.
urlconf_module = arg
if isinstance(urlconf_module, str):
urlconf_module = import_module(urlconf_module)
patterns = getattr(urlconf_module, ‘urlpatterns‘, urlconf_module)
app_name = getattr(urlconf_module, ‘app_name‘, app_name)
if namespace and not app_name:
raise ImproperlyConfigured(
‘Specifying a namespace in include() without providing an app_name ‘
‘is not supported. Set the app_name attribute in the included ‘
‘module, or pass a 2-tuple containing the list of patterns and ‘
‘app_name instead.‘,
)
namespace = namespace or app_name
# Make sure the patterns can be iterated through (without this, some
# testcases will break).
if isinstance(patterns, (list, tuple)):
for url_pattern in patterns:
pattern = getattr(url_pattern, ‘pattern‘, None)
if isinstance(pattern, LocalePrefixPattern):
raise ImproperlyConfigured(
‘Using i18n_patterns in an included URLconf is not allowed.‘
)
return (urlconf_module, app_name, namespace)
作者:masserd
来源:CSDN
原文:https://blog.csdn.net/zoulonglong/article/details/79612973
版权声明:本文为博主原创文章,转载请附上博文链接!
从include()函数可以看出来,这个函数有两个参数,一个arg,一个namespace,我在代码中也是两个参数,但是异常中提示了,没有提供app_name,还提示需要传入一个两元元组,从第六行代码,可以看出来,arg就是那个元组,且给app_name赋值了
urlconf_module, app_name = arg
经过一番面向百度debug,修改后代码为
from django.conf.urls import url,include
from django.contrib import admin
urlpatterns = [
url(r‘^admin/‘, admin.site.urls),
url(r‘^rbac/‘, include((‘rbac.urls‘,‘rbac‘),namespace=‘rbac‘)),
url(r‘^‘, include(‘web.urls‘)),
]
成功解决问题
原文地址:https://www.cnblogs.com/bruce-blogs/p/11184144.html
时间: 2024-10-18 00:32:08