Write a function:
def solution(A)
that, given an array A of N integers, returns the smallest positive integer (greater than 0) that does not occur in A.
For example, given A = [1, 3, 6, 4, 1, 2], the function should return 5.
Given A = [1, 2, 3], the function should return 4.
Given A = [−1, −3], the function should return 1.
Write an efficient algorithm for the following assumptions:
- N is an integer within the range [1..100,000];
- each element of array A is an integer within the range [−1,000,000..1,000,000].
def solution(A): ret = 1 c = len(A) for i in range(0, c, 1): if A[i] <= 0: continue if ret not in A: return ret else: ret += 1 return ret python list in 时间复杂度 列表元素存在性
原文地址:https://www.cnblogs.com/yuanjiangw/p/11149616.html
时间: 2024-10-11 03:44:03