137. Single Number II（js）

137. Single Number II

Given a non-empty array of integers, every element appears three times except for one, which appears exactly once. Find that single one.

Note:

Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?

Example 1:

Input: [2,2,3,2]
Output: 3

Example 2:

Input: [0,1,0,1,0,1,99]
Output: 99题意：给定一个数组，存在唯一一个数字只出现一次，其他数字出现3次，找到这个只出现一次的数字代码如下：

/**
 * @param {number[]} nums
 * @return {number}
 */
var singleNumber = function(nums) {
    let res=0;
    for(let i=0;i<32;i++){
        let sum=0;
        for(let j=0;j<nums.length;j++){
            sum+=(nums[j]>>i)&1;
        }
        res|=(sum%3)<<i;
    }
    return res;
};

原文地址：https://www.cnblogs.com/xingguozhiming/p/10952730.html