opencv3寻找最小包围矩形在图像中的应用-滚动条

 1 #include<opencv2/opencv.hpp>
 2 #include<iostream>
 3 #include<vector>
 4
 5 using namespace cv;
 6 using namespace std;
 7
 8 int g_nMinThred = 128, g_nMaxThred = 255;
 9 int g_nThick = 0;
10
11 int main()
12 {
13     Mat srcImage = imread("group.jpg");
14
15     namedWindow("【原图】", 0);
16     imshow("【原图】", srcImage);
17
18     createTrackbar("minthred", "【原图】", &g_nMinThred, 255, 0);
19     createTrackbar("maxthred", "【原图】", &g_nMaxThred, 255, 0);
20     createTrackbar("thick", "【原图】", &g_nThick, 100, 0);
21
22     //先对图像进行空间的转换（为了之后要提取二值图像）
23     Mat grayImage;
24     cvtColor(srcImage, grayImage, CV_BGR2GRAY);
25     //对图像进行滤波，达到较好的效果
26     GaussianBlur(grayImage, grayImage, Size(3, 3), 0, 0);
27     imshow("【滤波后的图像】", grayImage);
28
29     char key;
30     while (1)
31     {
32         //用边缘检测的方式获取二值图像
33         Mat cannyImage;
34         Canny(grayImage, cannyImage, g_nMinThred, g_nMaxThred, 3);
35
36         //在二值图像中提取轮廓
37         vector<vector<Point>> contours;
38         vector<Vec4i> hierarchy;
39         findContours(cannyImage, contours, hierarchy, RETR_TREE, CHAIN_APPROX_SIMPLE, Point(0, 0));
40
41         //对每个轮廓的点集 找逼近多边形
42         vector<vector<Point>> approxPoint(contours.size());
43         for (int i = 0; i < (int)contours.size(); i++)
44         {
45             //rectPoint变量中得到了矩形的四个顶点坐标
46             RotatedRect rectPoint = minAreaRect(contours[i]);
47             //定义一个存储以上四个点的坐标的变量
48             Point2f fourPoint2f[4];
49             //将rectPoint变量中存储的坐标值放到 fourPoint的数组中
50             rectPoint.points(fourPoint2f);
51
52             //根据得到的四个点的坐标  绘制矩形
53             for (int i = 0; i < 3; i++)
54             {
55                 line(cannyImage, fourPoint2f[i], fourPoint2f[i + 1]
56                     , Scalar(255, 255, 255), g_nThick);
57             }
58             line(cannyImage, fourPoint2f[0], fourPoint2f[3]
59                 , Scalar(255, 255, 255), g_nThick);
60         }
61
62         imshow("【绘制后的图像】", cannyImage);
63
64         key = waitKey(1);
65         if (key == 27)
66             break;
67     }
68
69     return 0;
70 }

顶

0

踩