winform中如何选中datagridview中的一行数据双击后跳转并将其显示在另一个页面的datagirdview中

Form1：

   public static string[] a;

  private void dataGridView1_DoubleClick(object sender, EventArgs e)//添加datagridview1的双击事件

        {

            try

            {

                int index = dataGridView1.CurrentRow.Index;

                a = new string[dataGridView1.ColumnCount];

                for (int i = 0; i < dataGridView1.ColumnCount; i++)

                {

                    a[i] = dataGridView1.Rows[index].Cells[i].Value.ToString();

                 }

                Form2 f2 = new Form2();

                f2.Show();

            }

            catch { }

        }

Form2://

  public Form2()

        {

            InitializeComponent();

            showGridView();

        }

  private void showGridView()

        {

            DataGridTextBoxColumn tb = new DataGridTextBoxColumn();

            dataGridView1.Rows.Add(tb);

            for (int i = 0; i < dataGridView1.ColumnCount;i++ )

                dataGridView1.Rows[dataGridView1.RowCount-2].Cells[i].Value = Form1.a[i];//根据AllowUserToAddRow属性选择最后一行，true时dataGridView1.RowCount-2,false时dataGridView1.RowCount-1

        }

原文地址：https://www.cnblogs.com/cnote/p/9061701.html