Keep on Truckin‘
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 10324 Accepted Submission(s): 7147
Problem Description
Boudreaux and Thibodeaux are on the road again . . .
"Boudreaux, we have to get this shipment of mudbugs to Baton Rouge by tonight!"
"Don‘t worry, Thibodeaux, I already checked ahead. There are three underpasses and our 18-wheeler will fit through all of them, so just keep that motor running!"
"We‘re not going to make it, I say!"
So, which is it: will there be a very messy accident on Interstate 10, or is Thibodeaux just letting the sound of his own wheels drive him crazy?
Input
Input to this problem will consist of a single data set. The data set will be formatted according to the following description.
The data set will consist of a single line containing 3 numbers, separated by single spaces. Each number represents the height of a single underpass in inches. Each number will be between 0 and 300 inclusive.
Output
There will be exactly one line of output. This line will be:
NO CRASH
if the height of the 18-wheeler is less than the height of each of the underpasses, or:
CRASH X
otherwise, where X is the height of the first underpass in the data set that the 18-wheeler is unable to go under (which means its height is less than or equal to the height of the 18-wheeler).
The height of the 18-wheeler is 168 inches.
Sample Input
180 160 170
Sample Output
CRASH 160
Source
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HDU，最水，英语看的脑子都是大的.
题意是说输入三个数，如果三个数都比168大，那么输出NO CRASH；否则输出第一个出现小于等于168的那个数！
如果你能从这段英文看出这个意思来，恭喜你，你赢了。反正我是没看出来！！
#include<iostream>
#include<cstdio>
using namespace std;
int main()
{
int a,b,c;
while(scanf("%d%d%d",&a,&b,&c)!=EOF)
{
if(a>168&&b>168&&c>168)
{
cout<<"NO CRASH"<<endl;
}
else if(a<168)
{
cout<<"CRASH "<<a<<endl;
}
else if(b<168)
{
cout<<"CRASH "<<b<<endl;
}
else if(c<168)
{
cout<<"CRASH "<<c<<endl;
}
}
return 0;
}
HDU-1037-Keep on Truckin'(HDU最水的题没有之一，为了练英语就来吧)