Given a m x n grid filled with non-negative numbers, find a path from top left to bottom right which minimizes the sum of all numbers along its path.
Note: You can only move either down or right at any point in time.
此题解法同Triangle
数字三角形。在此不再赘述。
class Solution { public: int minPathSum(vector<vector<int> > &grid) { size_t row = grid.size(); if(row == 0) return 0; size_t col = grid[0].size(); int **dp = new int *[row]; for(size_t i = 0; i < row; i++) { dp[i] = new int[col]; } dp[0][0] = grid[0][0]; for(size_t i = 1; i < row; i++) { for(size_t j = 1; j < col; j++) { dp[i][j] = 0; } } for(size_t i = 1; i < col; i++) dp[0][i] = dp[0][i - 1] + grid[0][i]; for(size_t i = 1; i < row; i++) dp[i][0] = dp[i - 1][0] + grid[i][0]; for(size_t i = 1; i < row; i++) for(size_t j = 1; j < col; j++) dp[i][j] = min(dp[i][j - 1],dp[i - 1][j]) + grid[i][j]; int result = dp[row - 1][col - 1]; for(size_t i = 0; i < row; i++) delete []dp[i]; delete []dp; return result; } };
时间: 2024-12-29 05:20:28