使用SQL语句求排名
表jh03有下列数据：
name score
aa 99
bb 56
cc 56
dd 77
ee 78
ff 76
gg 78
ff 50
1. 名次生成方式1 , Score重复时合并名次
SELECT * , Place=(SELECT COUNT(DISTINCT Score) FROM jh03 WHERE Score >= a.Score)
FROM jh03 a
ORDER BY Place
结果
Name Score Place
----------------
aa 99.00 1
ee 78.00 2
gg 78.00 2
dd 77.00 3
ff 76.00 4
bb 56.00 5
cc 56.00 5
ff 50.00 6
2. 名次生成方式2 , Score重复时保留名次空缺
SELECT * , Place=(SELECT COUNT(Score) FROM jh03 WHERE Score > a.Score) + 1
FROM jh03 a
ORDER BY Place
结果
Name Score Place
----------------
aa 99.00 1
ee 78.00 2
gg 78.00 2
dd 77.00 4
ff 76.00 5
bb 56.00 6
cc 56.00 6
ff 50.00 8
--成绩统计示例(交叉表)
--测试表
create table #t(xh varchar(3),xm varchar(10),km varchar(10),cj int)
insert into #t
select ‘001‘,‘张三‘,‘语文‘,80
union all select ‘001‘,‘张三‘,‘数学‘,85
union all select ‘002‘,‘李四‘,‘语文‘,90
union all select ‘002‘,‘李四‘,‘数学‘,80
union all select ‘003‘,‘王五‘,‘语文‘,70
union all select ‘003‘,‘王五‘,‘数学‘,78
--数据处理
declare @sql nvarchar(4000) , @sql1 nvarchar(4000)
select @sql = ‘‘ , @sql1 = ‘‘
select @sql = @sql + ‘,[‘ + km + ‘] = sum(case km when ‘‘‘ + km + ‘‘‘ then cj else 0 end)‘
,@sql1 = @sql1 + ‘,[‘ + km + ‘名次]=(select sum(1) from # where [‘ + km +‘] >= a.[‘ + km + ‘])‘
from(select distinct km from #t) a
exec(‘select xh 学号,xm 姓名‘[email protected]+‘,总成绩=sum(cj)
,总名次=(select sum(1) from(select xh,aa=sum(cj) from #t group by xh) aa where sum(a.cj)<=aa)
into # from #t a group by xh,xm
select *‘[email protected]+‘ from # a
‘)
drop table #t
/*--测试结果
学号 姓名 数学 语文 总成绩 总名次 数学名次 语文名次
---- ------ ------- -------- ----------- ----------- ----------- -----------
002 李四 80 90 170 1 2 1
003 王五 78 70 148 3 3 3
001 张三 85 80 165 2 1 2
--*/
用sql语句写排名