原题地址:https://oj.leetcode.com/problems/merge-k-sorted-lists/
题意:Merge k sorted linked lists and
return it as one sorted list. Analyze and describe its complexity.
解题思路:归并k个已经排好序的链表。使用堆这一数据结构,首先将每条链表的头节点进入堆中,然后将最小的弹出,并将最小的节点这条链表的下一个节点入堆,依次类推,最终形成的链表就是归并好的链表。
代码:
# Definition for singly-linked list.
# class ListNode:
# def __init__(self, x):
# self.val = x
# self.next = Noneclass Solution:
# @param a list of ListNode
# @return a ListNode
def mergeKLists(self, lists):
heap = []
for node in lists:
if node:
heap.append((node.val, node))
heapq.heapify(heap)
head = ListNode(0); curr = head
while heap:
pop = heapq.heappop(heap)
curr.next = ListNode(pop[0])
curr = curr.next
if pop[1].next:
heapq.heappush(heap, (pop[1].next.val, pop[1].next))
return head.next
[leetcode]Merge k Sorted Lists @ Python,布布扣,bubuko.com