来源:
http://www.cnblogs.com/itech/archive/2013/02/20/2919204.html
http://stackoverflow.com/questions/5703705/print-current-directory-using-perl?rq=1
1)
The following get the script‘s directory, which is not the same as the current directory. It‘s not clear which one you want.
use Cwd qw( abs_path );
useFile::Basename qw( dirname );
say dirname(abs_path($0));
or
usePath::Class qw( file );
say file($0)->absolute->dir;
or
useCwd qw( abs_path );
use Path::Class qw( file );
say file(abs_path($0))->dir;
The middle one handles symlinks different than the other two, I believe.
2)
To get the current working directory (pwd on many systems), you could use cwd() instead of abs_path:
useCwd qw();
my $path =Cwd::cwd();
print "$path\n";
Or abs_path without an argument:
useCwd qw();
my $path =Cwd::abs_path();
print "$path\n";
See the Cwd docs for details.
To get the directory your perl file is in from outside of the directory:
useFile::Basename qw();
my($name, $path, $suffix)=File::Basename::fileparse($0);
print "$path\n";
See the File::Basename docs for more details.
3)
You could use FindBin
:
use FindBin ‘$RealBin‘;
print "$RealBin\n";
FindBin
is a standard module that is installed when you install Perl. To get a list of the standard pragmatics and modules, see perldoc perlmodlib
.