solution
6 7 8都好说
对于1 2 3 4只需自己yy一个函数就行
(ps:我把L打成l....)
1 #include<cstdio> 2 #include<iostream> 3 #include<cstring> 4 #define ll long long 5 using namespace std; 6 const int N=1000006; 7 inline ll maxn(ll a,ll b){return a>b?a:b;} 8 inline ll minn(ll a,ll b){return a<b?a:b;} 9 10 int n,m; 11 ll v[N]; 12 struct son 13 { 14 ll max,min; 15 }; 16 son a[N*5]; 17 ll ji[N*5]; 18 void pushup(int x) 19 { 20 a[x].max=maxn(a[x<<1].max,a[x<<1|1].max); 21 a[x].min=minn(a[x<<1].min,a[x<<1|1].min); 22 } 23 void pushdown(int x) 24 { 25 if(ji[x]) 26 { 27 ji[x<<1]+=ji[x]; 28 ji[x<<1|1]+=ji[x]; 29 a[x<<1].max+=ji[x]; 30 a[x<<1].min+=ji[x]; 31 a[x<<1|1].min+=ji[x]; 32 a[x<<1|1].max+=ji[x]; 33 ji[x]=0; 34 } 35 } 36 void build(int l,int r,int x) 37 { 38 if(l==r) 39 { 40 a[x].min=a[x].max=v[l]; 41 return ; 42 } 43 int mid=(l+r)>>1; 44 build(l,mid,x<<1); 45 build(mid+1,r,x<<1|1); 46 pushup(x); 47 } 48 void addqu(int L,int R,ll c,int l,int r,int x) 49 { 50 if(L<=l&&r<=R) 51 { 52 a[x].max+=c; 53 a[x].min+=c; 54 ji[x]+=c; 55 return ; 56 } 57 pushdown(x); 58 int mid=(l+r)>>1; 59 if(L<=mid) 60 addqu(L,R,c,l,mid,x<<1); 61 if(mid<R) 62 addqu(L,R,c,mid+1,r,x<<1|1); 63 pushup(x); 64 } 65 void adddian(int pos,ll c,int l,int r,int x) 66 { 67 if(l==r) 68 { 69 a[x].min+=c; 70 a[x].max+=c; 71 return ; 72 } 73 int mid=(l+r)>>1; 74 pushdown(x); 75 if(pos<=mid) 76 adddian(pos,c,l,mid,x<<1); 77 else 78 adddian(pos,c,mid+1,r,x<<1|1); 79 pushup(x); 80 } 81 ll qq(int pos,int l,int r,int x) 82 { 83 if(l==r) 84 return a[x].max; 85 pushdown(x); 86 int mid=(l+r)>>1; 87 if(pos<=mid) 88 return qq(pos,l,mid,x<<1); 89 else 90 return qq(pos,mid+1,r,x<<1|1); 91 } 92 void Swap(int posx,int posy) 93 { 94 ll valx=qq(posx,1,n,1),valy=qq(posy,1,n,1); 95 adddian(posx,valy-valx,1,n,1); 96 adddian(posy,valx-valy,1,n,1); 97 } 98 ll zuoxiao(int L,int R,ll c,int l,int r,int x) 99 { 100 if(L<=l&&r<=R&&a[x].min>c) 101 return -1; 102 if(l==r) 103 return a[x].max<c?a[x].max:-1; 104 int mid=(l+r)>>1; 105 ll temp; 106 pushdown(x); 107 if(R>mid) 108 { 109 temp=zuoxiao(L,R,c,mid+1,r,x<<1|1); 110 return temp==-1?zuoxiao(L,R,c,l,mid,x<<1):temp; 111 } 112 else 113 return zuoxiao(L,R,c,l,mid,x<<1); 114 } 115 ll zuoda(int L,int R,ll c,int l,int r,int x) 116 { 117 if(L<=l&&r<=R&&a[x].max<c) 118 return -1; 119 if(l==r) 120 return a[x].max>c?a[x].max:-1; 121 int mid=(l+r)>>1; 122 ll temp; 123 pushdown(x); 124 if(R>mid) 125 { 126 temp=zuoda(L,R,c,mid+1,r,x<<1|1); 127 return temp==-1?zuoda(L,R,c,l,mid,x<<1):temp; 128 } 129 else 130 return zuoda(L,R,c,l,mid,x<<1); 131 } 132 ll youxiao(int L,int R,ll c,int l,int r,int x) 133 { 134 if(L<=l&&r<=R&&a[x].min>c) 135 return -1; 136 if(l==r) 137 return a[x].max<c?a[x].max:-1; 138 int mid=(l+r)>>1; 139 ll temp; 140 pushdown(x); 141 if(L<=mid) 142 { 143 temp=youxiao(L,R,c,l,mid,x<<1); 144 return temp==-1?youxiao(L,R,c,mid+1,r,x<<1|1):temp; 145 } 146 else 147 return youxiao(L,R,c,mid+1,r,x<<1|1); 148 } 149 ll youda(int L,int R,ll c,int l,int r,int x) 150 { 151 if(L<=l&&r<=R&&a[x].max<c) 152 return -1; 153 if(l==r) 154 return a[x].max>c?a[x].max:-1; 155 int mid=(l+r)>>1; 156 ll temp; 157 pushdown(x); 158 if(L<=mid) 159 { 160 temp=youda(L,R,c,l,mid,x<<1); 161 return temp==-1?youda(L,R,c,mid+1,r,x<<1|1):temp; 162 } 163 else 164 return youda(L,R,c,mid+1,r,x<<1|1); 165 } 166 int main(){ 167 //freopen("1.txt","r",stdin); 168 freopen("ccsworld.in","r",stdin); 169 freopen("ccsworld.out","w",stdout); 170 scanf("%d%d",&n,&m); 171 for(int i=1;i<=n;++i) 172 scanf("%lld",&v[i]); 173 174 build(1,n,1); 175 while(m--) 176 { 177 int kk; 178 int x,y; 179 ll w; 180 scanf("%d%d",&kk,&x); 181 if(kk==1)printf("%lld\n",zuoxiao(1,x,qq(x,1,n,1),1,n,1)); 182 else if(kk==2)printf("%lld\n",zuoda(1,x,qq(x,1,n,1),1,n,1)); 183 else if(kk==3)printf("%lld\n",youxiao(x,n,qq(x,1,n,1),1,n,1)); 184 else if(kk==4)printf("%lld\n",youda(x,n,qq(x,1,n,1),1,n,1)); 185 else if(kk==5){scanf("%d",&y);Swap(x,y);} 186 else if(kk==6){scanf("%d%lld",&y,&w);addqu(x,y,w,1,n,1);} 187 else if(kk==7){scanf("%d%lld",&y,&w);addqu(x,y,-w,1,n,1);} 188 } 189 //while(1); 190 return 0; 191 }
code
时间: 2024-10-22 09:10:54