判断字符串里是否有表情

刚遇到一个需求，发的字符里面不能有表情，下面是实现方法：

/**
 * 判断文字里面是否包含表情
 */
- (BOOL)isContainsEmoji:(NSString *)string {
    __block BOOL isEomji = NO;
    [string enumerateSubstringsInRange:NSMakeRange(0, [string length]) options:NSStringEnumerationByComposedCharacterSequences usingBlock:
     ^(NSString *substring, NSRange substringRange, NSRange enclosingRange, BOOL *stop) {
         const unichar hs = [substring characterAtIndex:0];
         if (0xd800 <= hs && hs <= 0xdbff) {
             if (substring.length > 1) {
                 const unichar ls = [substring characterAtIndex:1];
                 const int uc = ((hs - 0xd800) * 0x400) + (ls - 0xdc00) + 0x10000;
                 if (0x1d000 <= uc && uc <= 0x1f77f) {
                     isEomji = YES;
                 }
             }
         } else if (substring.length > 1) {
             const unichar ls = [substring characterAtIndex:1];
             if (ls == 0x20e3) {
                 isEomji = YES;
             }
         } else {
             if (0x2100 <= hs && hs <= 0x27ff && hs != 0x263b) {
                 isEomji = YES;
             } else if (0x2B05 <= hs && hs <= 0x2b07) {
                 isEomji = YES;
             } else if (0x2934 <= hs && hs <= 0x2935) {
                 isEomji = YES;
             } else if (0x3297 <= hs && hs <= 0x3299) {
                 isEomji = YES;
             } else if (hs == 0xa9 || hs == 0xae || hs == 0x303d || hs == 0x3030 || hs == 0x2b55 || hs == 0x2b1c || hs == 0x2b1b || hs == 0x2b50|| hs == 0x231a ) {
                 isEomji = YES;
             }
         }
     }];
    return isEomji;
}